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2 years ago

What is 2/7 into a percent

Mathematics

2 answers:

umka21 [38]2 years ago

3 0

28.57% is the answer

Ivan2 years ago

3 0

<h3>Answer:</h3>

<u><em>2/7 into percentage would be 28.571429%</em></u>

I hope this helped and have a good one!! Correct me if I am wrong. Did some outside research.

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What is 34 divided by 86.465

arsen [322]

Rounded up to 0.4

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8 0

3 years ago

What is the midpoint of the line segment with endpoints of (-2,-2) and (4,6)?

slamgirl [31]

Answer:

option (d) is correct.

The mid points of the line segment whose ends points are (-2,-2) and (4,6) is (1,2)

Step-by-step explanation:

Given: end points of a line segment as (-2,-2) and (4,6)

We have to find the mid points of the line segment whose ends points are given.

Mid point formula is stated as ,

For a line having end points as $\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right)$ , the mid point can be calculated as,

$\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)$

Here,

$\left(x_1,\:y_1\right)=\left(-2,\:-2\right),\:\left(x_2,\:y_2\right)=\left(4,\:6\right)$

Substitute in mid point formula, we get,

$=\left(\frac{4-2}{2},\:\frac{6-2}{2}\right)$

Solving further , we get,

$=\left(1,\:2\right)$

Thus, the mid points of the line segment whose ends points are (-2,-2) and (4,6) is (1,2)

Thus, option (d) is correct.

6 0

3 years ago

Read 2 more answers

During an intrumural basketball game, Team A scored 12 fewer points than Team B. Together, both teams scored a total of 144 poin

Lilit [14]

Answer:

A. 66

Step-by-step explanation:

Team A scored:

78+66=144

78-66=12 so Team A scored 12 fewer points than Team B

6 0

3 years ago

Please help me find the area of shaded region and step by step

Bumek [7]

Answer:

Part 1) $A=60\ ft^2$

Part 2) $A=80\ cm^2$

Part 3) $A=96\ m^2$

Part 4) $A=144\ cm^2$

Part 5) $A=9\ m^2$

Part 6) $A=(49\pi -33)\ in^2$

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

$A=bh$

where

b is the base of rectangle

h is the height of rectangle

$A=(12)(7)-(8)(3)$

$A=84-24$

$A=60\ ft^2$

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

$A=b^2$

where

b is the length side of the square

$A=(12)(8)-(4^2)$

$A=96-16$

$A=80\ cm^2$

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

$A=4(4)(5)+(4^2)$

$A=80+16$

$A=96\ m^2$

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

$A=(15^2)-(9^2)$

$A=225-81$

$A=144\ cm^2$

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

$A=\frac{1}{2}(b)(h)$

where

b is the base of triangle

h is the height of triangle

$A=\frac{1}{2}(6)(7)-(6)(2)$

$A=21-12$

$A=9\ m^2$

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

$A=\pi (7^2)-(3)(11)$

$A=(49\pi -33)\ in^2$

7 0

3 years ago

Solve r = 1/2m^2p for p

hoa [83]

You just have to arrange the equation such that the p is the only term at the left hand side of the equation. Express it in terms of r and m.

r = 1/2*m²*p
Divide both left and right hand side equations by 1/2*m²
p = r/(1/2 *m²)
Take the reciprocal of 1/2 and multiply it. The final answer is:
p = 2r/m²

7 0

3 years ago