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schepotkina [342]
4 years ago
8

Each student in your class must do 14 homework problems. There are 23 students in the class. How many problems will your teacher

have to grade?
Mathematics
1 answer:
Ganezh [65]4 years ago
4 0

Answer: 322

Step-by-step explanation:

23 students × 14 homework

=322 problems

The teacher will have to grade 322 problems

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For a certain horse race comma the odds in favor of a certain horse finishing in second placehorse race, the odds in favor of a
NikAS [45]

Answer:

0.33

Step-by-step explanation:

Let A denote an event. The odds of the horse finishing second is 33 to 67.

From the information, the total outcomes of event A is:

Total \ Outcomes, A=Favorable +Unfavorable\\\\=33+67\\\\=100

Hence, there are 100 total outcomes. The probability of the horse finishing second is calculated as:

p=\frac{n(A_f)}{n(A_u)}\\\\\\=p=\frac{33}{100}\\\\=0.33

Hence, the probability of finishing second is 0.33

7 0
3 years ago
16x-15-9x=13 how do I solve for x
dangina [55]
Add two like terms: 16x+(-9x)=7x
Add 15 to both sides: 7x=28
Divide 7 on both sides: x=4
7 0
3 years ago
Pre-Cal Help!! (Image Attached)
Jet001 [13]
To solve this type of questions, a practical way is to think of the 1.quadrant situation, that is, model the situation in right triangle trigonometry.

Check the picture.

For the moment let \displaystyle{ \cos\theta= \frac{8}{17} (we make it positive since we are modeling using a triangle.)

Using the Pythagorean theorem, the length of the side opposite to angle \theta is found to be 15 units.

We can see that the sine of theta is \displaystyle{ \sin\theta= \frac{opposite \ side}{hypotenuse}= \frac{15}{17}.

In the third quadrant, both sine and cosine of an angle are negative, so the actual values of the sine and cosine of theta are, eventually:

\displaystyle{ \sin\theta=- \frac{15}{17}, \displaystyle{ \cos\theta=- \frac{8}{17}.

Recall the double-angle identities (formulas):

\sin 2\theta=2\sin\theta\cos\theta, \cos2\theta=cos^2(\theta)-sin^2(\theta).

Using these identities and the ratios found above, we have:

\displaystyle{ \cos2\theta=cos^2(\theta)-sin^2(\theta)=(- \frac{8}{17})^2-(- \frac{15}{17})^2=\frac{64}{289}-\frac{225}{289}=\frac{-161}{289}

Similarly, applying the double angle formula for the sine we have:

\displaystyle{ \sin 2\theta=2\sin\theta\cos\theta=2\cdot(- \frac{8}{17})(- \frac{15}{17})=\frac{240}{289}

\displaystyle{ \tan2\theta= \frac{\sin 2\theta}{\cos 2\theta}= \frac{\frac{240}{289}}{\frac{-161}{289}}= -\frac{240}{161}


Answer:

\displaystyle{\cos2\theta=\frac{-161}{289}


\displaystyle{ \tan2\theta= -\frac{240}{161}

6 0
4 years ago
36.2 cm<br> 11 cm<br> 8 cm<br> 6 cm<br> What is the volume of the figure?<br><br> Please help!
Zarrin [17]

Answer: its 88 :]

Step-by-step explanation:

7 0
3 years ago
Find 2x^2y if x=-1 and y=3
Svetllana [295]

Answer:

6

Step-by-step explanation:

(-1)^2=(-1)(-1)=1

2(1)(3)=2*3=6

8 0
3 years ago
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