Answer:
4500 N
Explanation:
F = ma
= 1500 kg * 3 m/s^2 = 4500 N
edited to correct units !
Mass = Weight/g
= 1225 N/9.81 m/s^2
= 124.872579 kg
(rounded-off in 3 significant figures) = 125 kg
NOTE: I truly apologize if my answer is incorrect. I still hope this helped! :) (a brainliest would be much appreciated!)
Answer:
163.8 ft
Explanation:
In triangle ABD
= 155 ft
![Cos63 = \frac{BD}{AB} = \frac{BD}{155}\\BD = 155 Cos63 \\BD = 70.4 ft](https://tex.z-dn.net/?f=Cos63%20%3D%20%5Cfrac%7BBD%7D%7BAB%7D%20%3D%20%5Cfrac%7BBD%7D%7B155%7D%5C%5CBD%20%3D%20155%20Cos63%20%5C%5CBD%20%3D%2070.4%20ft)
![Sin63 = \frac{AD}{AB} = \frac{AD}{155} \\AD = 166 Sin63\\AD = 148 ft](https://tex.z-dn.net/?f=Sin63%20%3D%20%5Cfrac%7BAD%7D%7BAB%7D%20%3D%20%5Cfrac%7BAD%7D%7B155%7D%20%5C%5CAD%20%3D%20166%20Sin63%5C%5CAD%20%3D%20148%20ft)
Using Pythagorean theorem in triangle ADC
![AC^{2} = AD^{2} + DC^{2} \\175^{2} = 148^{2} + DC^{2} \\DC = 93.4 ft](https://tex.z-dn.net/?f=AC%5E%7B2%7D%20%3D%20AD%5E%7B2%7D%20%2B%20DC%5E%7B2%7D%20%5C%5C175%5E%7B2%7D%20%3D%20148%5E%7B2%7D%20%2B%20DC%5E%7B2%7D%20%5C%5CDC%20%3D%2093.4%20ft)
= distance between the anchor points
distance between the anchor points is given as
![d = BD + CD = 70.4 + 93.4\\d = 163.8 ft](https://tex.z-dn.net/?f=d%20%3D%20BD%20%2B%20CD%20%3D%2070.4%20%2B%2093.4%5C%5Cd%20%3D%20163.8%20ft)
Answer:
10-16= -4 so, 1.0x-4 is -4. So the answer is -4.
Explanation:
Answer:
312 kJ
Explanation:
The thermal energy contained in a cubic meter of air at room temperature (20 C) and one atmosphere (101 kPa) would be.
H = Cv * T + p * V
Being
Cv: specific heat of air at constant volme (0.72 kJ/(kg*K))
T: temperature in absolute scale (20C is 293 K)
Then:
H = 0.72 * 293 + 101 * 1 = 312 kJ
The only way to extract thermal energy from a body and turn it into useful work (such as charging a phone) is to exchange heat with it and a another colder body. So, with just the air at room temperature it is impossible to extract its heat energy.