All categories

3 years ago

Which is NOT a waste that is removed from the body by the excretory system?

Physics

2 answers:

oksian1 [2.3K]3 years ago

8 0

Answer:

C. Blood

Explanation:

All the other ones are removed from the body normally.

Julli [10]3 years ago

3 0

Answer:

The answer is C.

Explanation:

Blood is expelled from the body by the spleen, and most of the leftover compounds, i.e. iron, is recycled to make new red blood cells.

You might be interested in

The graph shows the motion of a car. Which segment shows that the car is slowing down? A, B, C, or D Graph:

shutvik [7]

Answer:

Segment c

Explanation:

5 0

3 years ago

Read 2 more answers

Question 4

bagirrra123 [75]

That's <em>false</em>. It's just the opposite. As you become more fit, your heart becomes able to accomplish more with each beat, so your resting heart rate DEcreases.

4 0

3 years ago

The standard unit of force in the metric system is the _____. A. gram B. pound C. newton D. kilogram

Snezhnost [94]

The answer is C. Newton

6 0

3 years ago

Read 2 more answers

The low-_____ areas in a sound wave are called rarefactions. A. period B. frequency C. energy D. density

Delicious77 [7]

You can picture a sound wave a lot like a Slinky wave . . . a
thicker, compressed blob moving along the path, with thinner,
stretched-out places before and after it.

The thicker parts of a sound wave, where the air is more dense,
are called compressions.

The thinner parts of a sound wave, where the air is less dense,
are called rarefactions.

4 0

3 years ago

Read 2 more answers

A 1.0 × 10^3 kg sports car is initially traveling at 15 m/s. The driver then applies the brakes for several seconds so that -25

algol13

Answer:

Ea = 112500[J]

Eb = 87500[J]

Explanation:

To solve this problem we must use the principle of energy conservation which tells us that the energy of a body plus the work done or applied by the body equals the final energy of a body.

This can be easily visualized by the following equation:

$E_{A}+E_{friction}=E_{B}$

Now we must define the energies at points A & B.

<u>For point A</u>

At point A we only have kinetic energy since it moves at 15 [m/s]

So the kinetic energy

$E_{A}=\frac{1}{2}*m*v_{A}^{2} \\E_{A}=\frac{1}{2} *1000*(15)^{2} \\E_{A}=112500[J]$

The final kinetic energy can be calculated as follows:

$112500-25000=E_{B}\\E_{B}=87500[J]$

8 0

3 years ago