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Nonamiya [84]
3 years ago
5

Which is NOT a waste that is removed from the body by the excretory system?

Physics
2 answers:
oksian1 [2.3K]3 years ago
8 0

Answer:

C. Blood

Explanation:

All the other ones are removed from the body normally.

Julli [10]3 years ago
3 0

Answer:

The answer is C.

Explanation:

Blood is expelled from the body by the spleen, and most of the leftover compounds, i.e. iron, is recycled to make new red blood cells.

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An open system starts with 52 J of mechanical energy. The energy changes
spayn [35]

Answer:

I think the answer is D,54 joules

5 0
2 years ago
At what angle of projectile range of maximum​
Agata [3.3K]

Answer:

45°

Explanation:

The textbooks say that the maximum range for projectile motion (with no air resistance) is 45 degrees.

7 0
3 years ago
Density: Two blocks, A and B, are put in a tank of water. Block A has a density of 1.21 g/cm³. Block B has a density of 1.37 g/c
stira [4]

Answer:

Block A

Explanation:

Block A will float higher in the water compared to the second Block.

The density of water is 1g/cm³.

According to the principle of floatation "an object that floats in a liquid will displace equal amount of fluid to the weight of the object".

A body will become more submerged in water if it has more density because density is the mass per volume of  body.

An object with a higher density than another will sink in the liquid of the one with lesser density.

  • Object A has lesser density and will float higher up and displace very little water.
  • Object B has higher density and will be more submerged.
4 0
3 years ago
A man is doing push-ups. he has a mass of 68 kg and his center of gravity is located at a horizontal distance of 0.70 m from his
lidiya [134]
Mass m = 68 kg
center of gravity from his palms x = 0.7 m
center of gravity from his feet x ' = 1 m
forces exerted by the floor on his palms and feet are F and F ' respectively.

with respect to palms :---------------------

( F*0 ) - (W * x ) + [ F ' * (x+x') ] = 0

             -mg*0.7 + F ' * 1.7 = 0    where W = weight = mg

F ' * 1.7 = mg * 0.7

          F ' = mg * 0.7 / 1.7

               = 68 *9.8 * ( 0.7 / 1.7 )

               = 274.4 N

with respect to feet :--------------------

( F ' * 0 ) -( W* x ' ) + [F * ( x + x') ] = 0

                -mg*1 + [ F * 1.7 ]= 0

                                 F = mg / 1.7

                                    = 392 N
7 0
3 years ago
Read 2 more answers
If the airman had a mass of 80 kg, find the magnitude of the air drag acting on him when he reached terminal velocity of 54 m/s
Vlad1618 [11]

The magnitude of the air drag is 784 N

Explanation:

An object falling down reaches the terminal velocity when the magnitude of the air drag acting on it becomes equal to the weight of the object. Mathematically, this condition can be written as:

F_D = mg

where

F_D is the magnitude of the air drag

m is the mass of the object

g is the acceleration of gravity

In this problem, we have

m = 80 kg is the mass of the airman

g=9.8 m/s^2 is the acceleration of gravity

Substituting into the formula, we find:

F_D = (80)(9.8)=784 N

Learn more about forces here:

brainly.com/question/8459017

brainly.com/question/11292757

brainly.com/question/12978926

#LearnwithBrainly

4 0
3 years ago
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