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Nonamiya [84]
3 years ago
5

Which is NOT a waste that is removed from the body by the excretory system?

Physics
2 answers:
oksian1 [2.3K]3 years ago
8 0

Answer:

C. Blood

Explanation:

All the other ones are removed from the body normally.

Julli [10]3 years ago
3 0

Answer:

The answer is C.

Explanation:

Blood is expelled from the body by the spleen, and most of the leftover compounds, i.e. iron, is recycled to make new red blood cells.

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Where does salt in the ocean come from
Bingel [31]

Answer:

Salt in the ocean comes from two sources: runoff from the land and openings in the seafloor. Rocks on land are the major source of salts dissolved in seawater. Rainwater that falls on land is slightly acidic, so it erodes rocks.

5 0
3 years ago
Read 2 more answers
A swimming pool has the shape of a right circular cylinder with radius 21 feet and height 10 feet. Suppose that the pool is full
AysviL [449]

Answer:

The water required to pump all the water to a platform 2 feet above the top of the pool is  is 6061310.32 foot-pound.

Explanation:

Given that,

Radius = 21 feet

Height = 10 feet

Weighing = 62.5 pounds/cubic

Work = 4329507.37572

Height = 2 feet

Let's look at a horizontal slice of water at a height of h from bottom of pool

We need to calculate the area of slice

Using formula of area

A=\pi r^2

Put the value into the formula

A=\pi\times21^2

A=441\pi\ feet^2

Thickness of slice t=\Delta h\ ft

The volume is,

V=(441\pi\times\Delta h)\ ft^3

We need to calculate the force

Using formula of force

F=W\times V

Where, W = water weight

V = volume

Put the value into the formula

F=62.5\times(441\pi\times\Delta h)

F=27562.5\pi\times\Delta h\ lbs

We need to calculate the work done

Using formula of work done

W=F\times d

Put the value into the formula

W=27562.5\pi\times\Delta h\times(10-h)\ ft\ lbs

We do this by integrating from h = 0 to h = 10

We need to find the total work,

Using formula of work done

W=\int_{0}^{h}{W}

Put the value into the formula

W=\int_{0}^{10}{27562.5\pi\\times(10-h)}dh

W=27562.5\pi(10h-\dfrac{h^2}{2})_{0}^{10}

W=27562.5\pi(10\times10-\dfrac{100}{2}-0)

W=4329507.37572

To pump 2 feet above platform, then each slice has to be lifted an extra 2 feet,

So, the total distance to lift slice is (12-h) instead of of 10-h

We need to calculate the water required to pump all the water to a platform 2 feet above the top of the pool

Using formula of work done

W=\int_{0}^{h}{W}

Put the value into the formula

W=\int_{0}^{10}{27562.5\pi\\times(12-h)}dh

W=27562.5\pi(12h-\dfrac{h^2}{2})_{0}^{10}

W=27562.5\pi(12\times10-\dfrac{100}{2}-0)

W=1929375\pi

W=6061310.32\ foot- pound

Hence, The water required to pump all the water to a platform 2 feet above the top of the pool is  is 6061310.32 foot-pound.

8 0
3 years ago
Stages of global warming
ddd [48]

Answer:

- Glaciers melt

- The seas rise

- Temperature changes

- Humans add heat trapping greenhouse gasses

7 0
3 years ago
A new roller coaster contains a loop-the-loop in which the car and rider are completely upside down. If the radius of the loop i
levacccp [35]

Answer:

The minimum speed must the car must be 13.13 m/s.

Explanation:

The radius of the loop is 17.6 m. We need to find the minimum speed must the car traverse the loop so that the rider does not fall out while upside down at the top.

We know that, mg be the weight of car and rider, which is equal to the centripetal force.

mg = \dfrac{mv^2}{r}\\v = \sqrt{rg}\\v = \sqrt{17.6\times 9.8}\\v = 13.13\ m/s\\

So, the minimum speed must the car must be 13.13 m/s.

5 0
3 years ago
A uniformly charged, straight filament 7.00m in length has a total positive charge of 2.00μC. An uncharged card-board cylinder 2
TEA [102]

The electric field at the surface of the cylinder is 51428V/m

Given data:

• The length of the charge is l=  7m.

• The charge is q = 2μC..

• The radius the cylinder is r = 10 cm

Since the filament length is so large as compared to the cylinder length that the infinite line of charge can be assumed.

The expression to calculate the electric field is given as,

E=2kλ/r

Here, λ is the linear charge density.

Substitute the values in the above equation,

E = (2×9×109N⋅m^2/C^2×2×10^−6C)/0.1m×7m

E = 51428N/C×(V/m)/(N/C)

=51428V/m

An electric charge is the property of matter where it has more or fewer electrons than protons in its atoms. Electrons carry a negative charge and protons carry a positive charge. Matter is positively charged if it contains more protons than electrons, and negatively charged if it contains more electrons than protons.

Learn more about charge here:

brainly.com/question/19886264

#SPJ4

4 0
1 year ago
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