Answer:
81.2 A
Explanation:
The magnetic field at the center of a current-carrying loop is given by
where
is the vacuum permeability
I is the current in the loop
R is the radius of the loop
In this problem, we have:
d = 12 cm is the diameter of the loop, so its radius is
R = d/2 = 12/2 = 6 cm = 0.06 m
is the magnetic field at the center
Therefore, the current in the loop must be:
-3 m/s
---------
per min
oh I think 8m/s to 3m/s to 0m/s
idk probably -0.08
Part (a): Specific volume
Specific volume, v = V/m, V = Volume of the tank, m = mass of CO in the tank
Therefore,
v = 1/4 = 0.25 m^3/kg
Part (b): Energy transferred in kJ
Work done, W = PΔt, where P = power = 14 W = 14 J/s, t = time = 1 hour = 60*60 = 3600 seconds
Therefore,
W = 14*3600 = 50400 J = 50.4 kJ
Part (c): Energy transferred by heat
ΔU = Q + W
Then,
Heat transferred by heat, Q = ΔU - W
But, ΔU = mΔu = 4 kg*10 kJ/kg = 40 kJ
Therefore,
Q = 40 - 50.4 = -10.4 kJ (negative sign indicates that heat is removed from the CO).
Answer:
a
b
Explanation:
From the question we are told that
The initial position of the particle is
The initial velocity of the particle is
The acceleration is
The time duration is
Generally from kinematic equation
=>
=>
Generally from kinematic equation
Here s is the distance covered by the particle, so
=>
Generally the final position of the particle is
=>
=>
A point of a single dimension, a plane of two, and 3D involving the depth of the third dimension.