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Lena [83]
4 years ago
14

The titration of a 20.0-mL sample of an H2SO4 solution of unknown concentration requires 22.60 mL of a 0.158 M KOH solution to r

each the equivalence point. What is the concentration of the unknown H2SO4 solution ? Express your answer in molarity to three significant figures.
Chemistry
1 answer:
soldier1979 [14.2K]4 years ago
5 0

Answer:

M₁ = 0.178 M

Explanation:

In case of titration , the following formula can be used -

M₁V₁ = M₂V₂

where ,  

M₁ = concentration of acid ,  

V₁ = volume of acid,

M₂ = concentration of base ,

V₂ = volume of base,

from , the question ,  

M₁ = ?

V₁ = 20.0 mL

M₂ = 0.158 M

V₂ = 22.60 mL

Using the above formula , the molarity of the acid , can be calculated as ,  

M₁V₁ = M₂V₂

M₁ * 20.0 mL = 0.158 M * 22.60 mL

M₁ = 0.178 M

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What element is stored in the shells and skeltyons of living organisims?
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Answer:

carbon

Explanation:

Many organisms use carbon to make calcium carbonate, a building material of shells and skeletons. Other chemical processes create calcium carbonate in the water. The using up of carbon by biological and chemical processes allows more carbon dioxide to enter the water from the atmosphere.

8 0
3 years ago
If you have a cup of water at 35 degrees Celsius, and a bath tub of water at 35 degrees Celsius which will melt the most ice and
ZanzabumX [31]
The bathtub of water would melt the most ice because it has a larger area
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3 years ago
100.0 mL of 3.8M NaCN, the minimum lethal concentration of sodium cyanide in blood serum
9966 [12]

The given question is incomplete. The complete question is:

Calculate the number of moles and the mass of the solute in each of the following solution: 100.0 mL of 3.8 × 10−5 M NaCN, the minimum lethal concentration of sodium cyanide in blood serum

Answer: The number of moles and the mass of the solute are 0.38\times 10^{-5} and 18.62\times 10^{-5}g respectively

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute

V_s = volume of solution in ml

3.8\times 10^{-5}M=\frac{n\times 1000}{100.0}

n=0.38\times 10^{-5}

n = moles of NaCN = \frac{\text {given mass}}{\text {Molar mass}}

0.38\times 10^{-5}=\frac{x}{49g/mol}

x=18.62\times 10^{-5}g

Thus the number of moles and the mass of the solute are 0.38\times 10^{-5} and 18.62\times 10^{-5}g respectively

6 0
3 years ago
The value of Δ for the [CrF6]^3- complex is 182 kJ/mol.Calculate the expected wavelength of the absorption corresponding to prom
anastassius [24]

Answer:

6.63*10-7 m

Explanation:

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8 0
4 years ago
What we call "tin cans" are really iron cans coated with a thin layer of tin. The anode is a bar of tin and the cathode is the i
UNO [17]

Answer:

Fe (s) + Sn^{2+} (aq)\rightarrow Fe^{2+} (aq) + Sn (s)

Explanation:

Although the context is not clear, let's look at the oxidation and reduction processes that will take place in a Fe/Sn system.

The problem states that anode is a bar of thin. Anode is where the process of oxidation takes place. According to the abbreviation 'OILRIG', oxidation is loss, reduction is gain. Since oxidation occurs at anode, this is where loss of electrons takes place. That said, tin loses electrons to become tin cation:

Sn (s)\rightarrow Sn^{2+} (aq) + 2e^-

Similarly, iron is cathode. Cathode is where reduction takes place. Reduction is gain of electrons, this means iron cations gain electrons and produce iron metal:

Fe^{2+} (aq) + 2e^-\rightarrow Fe (s)

The net equation is then:

Sn (s) + Fe^{2+} (aq)\rightarrow Fe (s) + Sn^{2+} (aq)

However, this is not the case, as this is not a spontaneous reaction, as iron metal is more reactive than tin metal, and this is how the coating takes place. This implies that actually anode is iron and cathode is tin:

Actual anode half-equation:

Fe (s)\rightarrow Fe^{2+} (aq) + 2e^-

Actual cathode half-equation:

Sn^{2+} (aq) + 2e^-\rightarrow Sn (s)

Actual net reaction:

Fe (s) + Sn^{2+} (aq)\rightarrow Fe^{2+} (aq) + Sn (s)

6 0
3 years ago
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