1 mol of atoms contains Avogadro's number of atoms. Avogadro's number =6.022140857(74)×10^23
So there are
1
4
×
N
A
nitrogen atoms in such a molar quantity of nitric oxide, approx.
1.5
×
10
23
individual nitrogen atoms. How many OXYGEN atoms in such a quantity?
Here I use
N
A
as I would use any other collective number: a dozen, a score, a gross. I am perfectly free to do so, because any physical scientist knows precisely what I mean by a
mole
.
Answer:
The coordination sphere of a complex consists of <u><em>the central metal ion and the ligands bonded to it.</em></u>
Explanation:
The Coordination Compounds are sets of a central metal ion attached to a group of molecules or ions that surround it. They are also called metal complexes or simply complexes. Then they are compounds that have a central atom surrounded by a group of molecules or ions, the latter called ligands.
The central atom must have empty orbitals capable of accepting pairs of electrons, with the transition metals being the ones with the greatest tendency. Because of this, they can act as Lewis acids (electron pair acceptors). The ligands have unshared electron pairs, then acting as Lewis bases (electron pair donors).
When forming a complex, it is said that the ligands coordinate to the metal and the central metal and the ligands attached to it constitute the coordination sphere of the complex.
Finally, <u><em>the coordination sphere of a complex consists of the central metal ion and the ligands bonded to it.</em></u>
Answer:
The overall cell potential must be positive.
Explanation:
What must be true for a spontaneous reaction in an electrochemical cell?
- The overall cell potential must be positive. YES. This is by convention.
- The overall cell potential must be negative. NO. By convention, a negative cell potential means the cell is not spontaneous.
- The cathode’s standard reduction potential must be positive. NO. It only has to be higher than the anode's standard reduction potential.
- The cathode’s standard reduction potential must be negative. NO. It only has to be higher than the anode's standard reduction potential.
Answer:
132 m/s
Explanation:
So, you divide the distance by the time.
Answer:
Explanation:
Total cards available = 8
Probability of drawing Blue = 5/8
Probability of drawing Yellow = 3/8
Step 1
Probability of drawing blue card first = 5/8.
Since, the first drawn blue card is NOT replaced; Total card available = 7
Then, probability of drawing blue card again = 4/7.
Finally, the probability of drawing TWO blue cards = 5/8 × 4/7
= 5/14.
So, the number belonging to the green box is 5.