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fredd [130]
3 years ago
8

Find the area of the triangle A. 26 yd2 B. 12yd2 C. 24yd2 D. 36yd2

Mathematics
1 answer:
pogonyaev3 years ago
8 0
I think u should choose there  A or C 
if it is not them then u can rue out two of the wrong answers and u would have a 50/50 chance of getting the right one i hoped this helped plz tell me if u got the wrong choice so i can help u better next time.
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Find the equation of this line. y= [?]x+[?]
DochEvi [55]

Answer:

y=3x-4

Step-by-step explanation:

Hi there!

Slope-intercept form: y=mx+b where <em>m</em> is the slope and <em>b</em> is the y-intercept (the value of y when x=0)

<u>1) Determine the slope (</u><u><em>m</em></u><u>)</u>

m=\displaystyle\frac{y_2-y_1}{x_2-x_1} where two points that fall on the line are (x_1,y_1) and (x_2,y_2)

On the graph, two points are highlighted for us: (0,-4) and (2,2). Plug these into the formula:

m=\displaystyle\frac{2-(-4)}{2-0}\\\\m=\displaystyle\frac{2+4}{2}\\\\m=\displaystyle\frac{6}{2}\\\\m=3

Therefore, the slope of the line is 3. Plug this into y=mx+b:

y=3x+b

<u>2) Determine the y-intercept (</u><u><em>b</em></u><u>)</u>

y=3x+b

Recall that the y-intercept occurs when x=0. Given the point (0,-4), the y-intercept is therefore -4. Plug this into y=3x+b:

y=3x+(-4)\\y=3x-4

I hope this helps!

5 0
2 years ago
Given that LM and LN are tangent to the circle and that the measure of angle MLN = 75.86, find the measure of arc MN.
siniylev [52]

we know that

The measure of the external angle is the semidifference of the arcs that it covers

so

∠MLN=(1/2)*(mayor arc MN-minor arc MN)

Let

x------> minor arc MN

major arc MN=360-x

substitute in the formula above

∠MLN=(1/2)*(mayor arc MN-minor arc MN)

75.86=(1/2)*(360-x-x)------> 151.72=(360-2x)------>360-151.72=2x

x=104.14°

therefore

the answer is

the measure of arc MN (minor arc) is 104.14°

7 0
3 years ago
What is the length of the mid-segment DE?
astraxan [27]

Answer:

The midsegment is one-half the length of the base

5 0
3 years ago
A recommendation for wheelchair ramps is that the rise-to-run ratio be no greater than 1:12. This ensures that the ramps are nav
patriot [66]

Answer:

a. 12 feet b. 12 feet 0.5 inches c. 8.33 %

Step-by-step explanation:

a. How far out horizontally on the ground will it protrude from the building?

Since the rise to run ratio is 1:12 and the building is 12 inches off the ground, let x be the horizontal distance the ramp protrudes.

So, by ratios rise/run = 1/12 = 12/x

1/12 = 12/x

x = 12 × 12

x = 144 inches

Since 12 inches = 1 foot, 144 inches = 144 × 1 inch = 144 × 1 foot/12 inches = 12 feet

b. How long should the ramp be?

The length of the ramp, L is gotten from Pythagoras' theorem since the ramp is a right-angled triangle with sides 12 inches and 144 inches respectively.

So, L = √(12² + 144²)

= √[12² + (12² × 12²)]

= 12√(1 + 144)

= 12√145

= 12 × 12.042

= 144.5 inches

Since 12 inches = 1 foot, 144.5 inches = 144 × 1 inch + 0.5 inches = 144 × 1 foot/12 inches + 0.5 inches = 12 feet 0.5 inches

c. What percent grade is the ramp?

The percentage grade of the ramp = rise/run × 100 %

= 12 inches/144 inches × 100 %

= 1/12 × 100 %

= 0.0833 × 100 %

= 8.33 %

6 0
3 years ago
If 18 cupcakes cost $44.64. How much would 20 cupcakes cost?
Nonamiya [84]
20 cupcakes will cost $49.60. You divide 44.64 by 18 and get 2.48. Multiply 2.48 by two getting 4.96. Then you add 44.64 and 4.96 together and get your answer.
5 0
3 years ago
Read 2 more answers
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