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3 years ago

What is greater 3 x 1/10 plus 4 x 1/100 plus 8x 1/1000 greater than one and two tenths

2 answers:

5 0

So, first let's change these numbers into decimal form:
3*0.1 + 4*0.01 + 8*0.001 ? 1.2
Multiply:
0.3 + 0.04 + 0.008 ? 1.2
0.348 < 1.2
One and two tenths is larger.
Hopefully this is what you're asking, as this question is unclear

skelet666 [1.2K]3 years ago

5 0

3*0.1 + 4*0.01 + 8*0.001 ? 1.2

Multiply:

0.3 + 0.04 + 0.008 ? 1.2

0.348 < 1.2

One and two tenths is larger

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I've been having struggles with math recently and would greatly appreciate help

BARSIC [14]

ANSWER:

$-4x^3+4x^2-4x+2$

STEP-BY-STEP EXPLANATION:

We have the following expression:

$(4x^3+6x^2-9x+1)-(8x^3+2x^2-5x-1)$

In order to operate, we must first break the parentheses and then group similar terms, like this:

$\begin{gathered} 4x^3+6x^2-9x+1-8x^3-2x^2+5x+1 \\ (4x^3-8x^3)+(6x^2-2x^2)+(-9x+5x)+(1+1) \\ \text{ therefore:} \\ -4x^3+4x^2-4x+2 \\ (4x^3+6x^2-9x+1)-(8x^3+2x^2-5x-1)=-4x^3+4x^2-4x+2 \end{gathered}$

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1 year ago

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3 years ago

How would you solve a problem in time travel if you you departing at 1:10 PM EST and arriving at 8:29 PM PST.

In-s [12.5K]

Answer:

you would figure out the time in either pst or est and find out the time

Step-by-step explanation:

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1:10 PM

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3 years ago

Which of the following equations represent a graph with the most rapid rate of change?

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3 years ago

Given the rule: an=7(1/2)n-1 identify the first term

Shkiper50 [21]

Answer:

using the rule given: 2.5
using an exponential rule: 7

Step-by-step explanation:

Evaluating the linear rule given, for n = 1, we have ...

a1 = 7(1/2)(1) -1 = 7/2 -1 = 5/2 = 2.5

_____

We suspect you may intend the exponential function ...

an = 7(1/2)^(n-1)

Then, for n = 1, we have ...

a1 = 7(1/2)^(1 -1) = 7(1) = 7 . . . . the first term is 7

_____

When writing an exponential expression in plain text, it requires the exponential operator, a caret (^). If the exponent contains any arithmetic, as this one does, it must be enclosed in parentheses.

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3 years ago