Ok so first we find the equation that equals one variable.
2y = -x + 9
3x - 6y = -15
We solve for y.
2y = -x + 9
y = -x/2 + 9/2
Then we plug in this y value into the other equation to keep only one variable so we can solve for it.
3x - 6y = -15
3(-x + 9/2) - 6y = -15
-3x + 27/2 - 6y = -15
-9y + 27/2 = -15
-9y = 3/2
-y = 3/18
y = -3/18
Then we plug in this numerical y-value into the first equation which we found out by solving an equation for y.
y = -x/2 + 9/2
-3/18 = -x/2 + 9/2
-84/18 = -x/2
-x = 9 1/3
x = -28/3
Your answer would be (-28/3, -3/18)
Hope this helps!
Answer:
(-∞,∞)
Step-by-step explanation:
The domain is all possible x values of the function
There are no constraints or holes for this and therefore the domain is all real numbers
Distribute +1
78=1/2x+x-6
combine like terms
1=(2/2)
(1/2)+(2/2)= 3/2
78=3/2x-6
Add 6 to both sides
84=3/2x
Divide by (3/2)
x=$56=adult ticket
Child ticket = x-6=56-6=$50
$50
Answer:
Experiment
Step-by-step explanation:
Base on the scenario been described in the question, where Mrs. Reynolds has many (over a hundred) houseplants of many different types including philodendrons, ferns, spider plants, cacti, tomatoes, pineapples, this is a typical example of experiment .
An experiment is a procedure carried out to support, refute, or validate a hypothesis. Experiments provide insight into cause-and-effect by demonstrating what outcome occurs when a particular factor is manipulated
Answer:
See explanation
Step-by-step explanation:
Let x be the number of hours per week Nando is brisk walking and y be the number of hours per week Nando is biking at a moderate pace.
For the first month, he needs to exercise at most five hours per week, then
Brisk walking burns about 350 calories per hour, then it burns 350x calories per x hours.
Biking at a moderate pace burns about 700 calories per hour, then it burns 700y calories per y hours.
Nando must burn at least 2,000 calories per week, so
You get the system of two inequalities:
The attached graph shows the solution set to this system of inequalities. In this diagram, red region represents the solution set to the first inequality, blue region represents the solution set to the second inequality and their intersection is the solution set to the system of two inequalities.
