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Strike441 [17]
2 years ago
6

Write the equation of the line in​ slope-intercept form that passes through the points​ (-12, -6) and​ (8, 9).

Mathematics
1 answer:
irakobra [83]2 years ago
4 0

Answer:

(-10.5, -2)

Step-by-step explanation:

This is wrong btw haha

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find the equation of a cubic function whose graph passes through points (3,0) and (1,4) and is tangent to x-axis at the origin
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Answer:

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Step-by-step explanation:

<em><u>Preliminary Remark</u></em>

If a cubic is tangent to the x axis at 0,0

Then the equation must be related to y = a*x^2(x - h)

<em><u>(3,0)</u></em>

If the cubic goes through the point (3,0), then the equation will become

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<em><u>From the second point, we get</u></em>

4 = ax^2(x - 3)

4 = a(1)^2(1 - 3)

4 = a(-2)

a = 4 / - 2

a = -2

<em><u>Answer</u></em>

y = -2x^2(x - 3)

 

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