Answer:
a
The estimate is 
b
Method B this is because the faulty breaks are less
Step-by-step explanation:
The number of microchips broken in method A is 
The number of faulty breaks of method A is 
The number of microchips broken in method B is 
The number of faulty breaks of method A is 
The proportion of the faulty breaks to the total breaks in method A is


The proportion of the faulty to the total breaks in method B is

For this estimation the standard error is

substituting values


The z-values of confidence coefficient of 0.95 from the z-table is

The difference between proportions of improperly broken microchips for the two breaking methods is mathematically represented as
![K = [p_1 - p_2 ] \pm z_{0.95} * SE](https://tex.z-dn.net/?f=K%20%3D%20%5Bp_1%20-%20p_2%20%5D%20%5Cpm%20z_%7B0.95%7D%20%2A%20SE)
substituting values
![K = [0.08 - 0.07 ] \pm 1.96 *0.0186](https://tex.z-dn.net/?f=K%20%3D%20%5B0.08%20-%200.07%20%5D%20%5Cpm%201.96%20%2A0.0186)

The interval of the difference between proportions of improperly broken microchips for the two breaking methods is

It’s the first one. I think
Not sure if it's one of the answer you listed.
The • means multiplication, so it would be
54 times 58, which equals 3,132.
Answer:
The answer would be 0.36
Step-by-step explanation:
57+57+63
=177
no, there are more students than seats, (unless the players are included in the number?) in that case are there 27 players in a game? idk basketball, on the bench maybe?