The answer would be 51y+140
57.4 because u add all the side up and u get a answer
7 multiply by three u get 21 then add it to the number 28 add u get the answer 49
I'm here buddy,
so, let's take the value of the two bags with equal weight as x.
= x + x + (x +
) = 
= 3x +
= 
= 3x =
- 
( let's take the LCM of 4 and 5 = 20
= 3x =
- 
= 3x = 
= x =
÷
=
×
= 
So, the weight of the equal bags are
and the weight of the third bag ( heavy one ) is
+
=
+
= 
1st bag =
kg
2nd bag =
kg
3rd bag =
kg
Hope it helps...