The question is incomplete. The complete question is :
The population of a certain town was 10,000 in 1990. The rate of change of a population, measured in hundreds of people per year, is modeled by P prime of t equals two-hundred times e to the 0.02t power, where t is measured in years since 1990. Discuss the meaning of the integral from zero to twenty of P prime of t, d t. Calculate the change in population between 1995 and 2000. Do we have enough information to calculate the population in 2020? If so, what is the population in 2020?
Solution :
According to the question,
The rate of change of population is given as :
in 1990.
Now integrating,

![$=\frac{200}{0.02}\left[e^{0.02(20)}-1\right]$](https://tex.z-dn.net/?f=%24%3D%5Cfrac%7B200%7D%7B0.02%7D%5Cleft%5Be%5E%7B0.02%2820%29%7D-1%5Cright%5D%24)
![$=10,000[e^{0.4}-1]$](https://tex.z-dn.net/?f=%24%3D10%2C000%5Be%5E%7B0.4%7D-1%5D%24)
![$=10,000[0.49]$](https://tex.z-dn.net/?f=%24%3D10%2C000%5B0.49%5D%24)
=4900





This is initial population.
k is change in population.
So in 1995,



In 2000,


Therefore, the change in the population between 1995 and 2000 = 1,163.
Answer:0.001
x=the number of workers taking the bus to work
p= probability of success =(15/100) = 0.15
q= probability of failure =1- p = 0.85
P(X=6) = 10C6(0.15)^6(0.85)^4
= 0.001
Answer:
I got 0 or 18/5
Step-by-step explanation:
Centigram, milligram, gram, kilogram
Answer:
<em>The simple interest is $11,212.5 and the equation to determine Josh's simple interest is I = PRT/100</em>
Step-by-step explanation:
The formula for calculating simple interest is expressed as;
SI = Principal * rate * time/100
SI = 50,000 * 6.9*39/100*12
SI = 500*6.9*39/12
SI = 134,550/12
SI = 11,212.5
<em>Hence the simple interest is $11,212.5 and the equation to determine Josh's simple interest is I = PRT/100</em>
P is the amount borrowed
R is the interest rate
T is the time in years