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3 years ago

Help me this please, i love u

Mathematics

1 answer:

RSB [31]3 years ago

4 0

Answer:

Pics block

Step-by-step explanation:

You might be interested in

For the last basketball game, 381 tickets were sold. Adult tickets sold for $7, and student tickets sold for $3. How many adult

vovikov84 [41]

Answer: 96 adult tickets were sold.

Step-by-step explanation:

Let x represent the number of adult tickets that were sold.

Let y represent the number of students tickets that were sold.

For the last basketball game, 381 tickets were sold. This means that

x + y = 381

Adult tickets sold for $7, and student tickets sold for $3. If the ticket sales totaled 1,527, it means that

7x + 3y = 1527 - - - - - - - - - - - -1

Substituting x = 381 - y into equation 1, it becomes

7(381 - y) + 3y = 1527

2667 - 7y + 3y = 1527

- 7y + 3y = 1527 - 2667

- 4y = - 1140

y = - 1140/- 4

y = 285

x = 381 - y = 381 - 285

x = 96

4 0

3 years ago

Click on the pic and pls help!!

Natasha_Volkova [10]

Answer:

x = 43.9

Step-by-step explanation:

sin 20° = 15/x

0.3420 = 15/x

x = 43.86

6 0

3 years ago

I'm completely lost?

aliya0001 [1]

13000-5600=7400...that's about it, just multiply then subtract

4 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=5%28sin%28t%29%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%2Bycos%28t%29%29%29%3Dcos%28t%29%20%20%28sin%28

Nataliya [291]

Assuming you mean

$5\sin t\dfrac{\mathrm dy}{\mathrm dt}+5y\cos t=\cos t\sin^2t$

This ODE is linear in $y$ , and you can already contract the left hand side as the derivative of a product:

$\dfrac{\mathrm d}{\mathrm dt}\left[5y\sin t\right]=\cos t\sin^2t$

Integrating both sides with respect to $t$ yields

$5y\sin t=\displaystyle\int\cos t\sin^2t\,\mathrm dt$
$5y\sin t=\dfrac13\sin^3t+C$
$y=\dfrac1{15}\sin^2t+C\csc t$

Given that $y\left(\dfrac\pi2\right)=9$ , we have

$9=\dfrac1{15}\sin^2\dfrac\pi2+C\csc\dfrac\pi2$
$9=\dfrac1{15}+C$
$C=\dfrac{134}{15}$

so that the particular solution over the interval is

$y=\dfrac1{15}\sin^2t+\dfrac{134}{15}\csc t$