3 years ago

$1500 at 4% for five years what is the balance of the account

1 answer:

4 0

Amount of Interest (I) = P * R * T /100
I = 1500 * 5 * 4 /100
I = 300

Balance = Initial amount + Interest amount
B = 1500 + 300 = 1800

In short, Your Answer would be $1800

Hope this helps!

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Answer:

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Step-by-step explanation:

Given:

$a^2x^5b,,\ -0.6axb^2,\ and\ 0.6a^2b^3$

Required

Multiply

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$a^2x^5b * -0.6axb^2\ * \ 0.6a^2b^3$

Split the above expression

$a^2*x^5*b * -0.6*a*x*b^2\ * \ 0.6*a^2*b^3$

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Apply first law on indices

$-0.36 * a^{2+1+2} *b^{1+2+3} *x^{5+1}$

$-0.36 * a^{5} *b^{6} *x^{6}$

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Hence, $a^2x^5b * -0.6axb^2\ * \ 0.6a^2b^3$ is equivalent to $-0.36 a^{5}b^{6} x^{6}$

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