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maksim [4K]
3 years ago
14

Three mangos and two apples sell for $1.25. Five mangos and one apple sell for $1.50. What is the cost for each mango

Mathematics
1 answer:
Pepsi [2]3 years ago
6 0

Answer:

mango is .25 and apple is .25 i took a picture of my work- dont mind the purple paper it was my notes packet xdd

Step-by-step explanation:

You might be interested in
If each pound of beef costs $3.69, how much does 2 pounds cost? Round to the nearest cent.
Kryger [21]

Answer: Two pounds of beef costs $7.38.

Step-by-step explanation:

Multiply the cost for one pound by the amount of pounds you need.

$3.69×2=$7.38

I hope this helps!!

6 0
2 years ago
Read 2 more answers
Can someone help me with this?
Natalija [7]

use the Pythagoras theorem method

a squared plus b squared equals c square

8 0
3 years ago
in the figures below the cube shaped box is 6 inches wide and the rectangular box is 10 inches long 4 inches wide and 4 inches h
IRINA_888 [86]
<span>The cube’s sides measures 6 inches and the measurement for the rectangular box is that it is 10 inches long, 4 inches thick and 4 inches high. To compute for the volume of a cube you must use the formula of V = a3 and for the rectangular prism is V = l x w x h.</span>
<span>Cube:    V = 6^3
</span>              <span>V = 216 inches^3</span>
<span>Rectangular Prism:       V = 10 x 4 x 4</span> <span>             
                                       V = 160 inches^3</span>
To identify how much greater the volume the cube from the rectangular box we subtract their volumes.
N = C – R where N stands for the unknown C for the volume of cube and R for the volume of Rectangular Box <span>
N = 216 inches^3 – 160 inches^3
</span> <span>N = 56 inches^3</span> <span>
So the cube is 56 inches3 greater than the rectangular box.</span>


4 0
3 years ago
Read 2 more answers
Find lim x-&gt;2 for f(x)=
TiliK225 [7]

LHL in not equal to RHL , Therefore the limit does not exists , Option D is the answer.(none)

<h3>What is the limit of a function ?</h3>

The limit of a function at a certain point is the value that the function approaches as the argument of the function approaches the same point.

It is given that

lim x->2 for f(x)

\lim_{x \rightarrow 2^-}f(x) = \lim_{x\rightarrow 2^+}f(x)

f(x) = 2x+1 x ≤2

f(x)= x² , x >2

When both the function tends to 2

Left Hand Limit

f(x) = 2 *2 +1

f(x) = 5

Right Hand Limit

f(x) = x² ,

f(x) = 4

LHL in not equal to RHL , Therefore the limit does not exists.

To know more about Limit of a Function

brainly.com/question/7446469

#SPJ1

8 0
2 years ago
Please go through step by step so I can also learn the correct way. Will thank the person who goes step by step
juin [17]

Answer:

5.848 in

Step-by-step explanation:

Divide the piece of cardboard into nine equal squares of side z.

The centre square is the base of the cube.

When you cut out the corner squares and fold up the sides, you will have a cube with edge length z.

The cube must have a volume of 200 in³.

    V = z³

200 = z³

    z = \sqrt[3]{200}

    z = \sqrt[3]{8\times25}

    z = 2\sqrt[3]{25}

    z = 2 × 2.924

    z = 5.848 in

The edge length of the cube is 5.848 in.

8 0
3 years ago
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