Answer:
(a) There are asymptotes at x=3/2 and x=-1/3
Step-by-step explanation:
The denominator zeros can be found by factoring:
f(x) = (x +1)/((2x -3)(3x +1))
Neither of the denominator factors is cancelled by the numerator factor, so each represents a vertical asyptote, not a function hole.
The asymptotes are at the values of x where the denominator is zero:
2x -3 = 0 ⇒ x = 3/2
3x +1 = 0 ⇒ x = -1/3
.17 because there is a zero behind the 7! .170 and .165. .17 is bigger
<h3>x is 2 and y is -2</h3>
<em><u>Solution:</u></em>
Given that,
3x-2 equal x-y equals 4
Which means,
3x - 2 = x - y = 4
Therefore,
x - y = 4
Also,
3x - 2 = 4
Simplify above expression
3x - 2 = 4
3x = 4 + 2
3x = 6
Divide both sides by 3
x = 2
Substitute x = 2 in x - y = 4
2 - y = 4
y = 2 - 4
y = -2
Thus x is 2 and y is -2
Answer:
huh
Step-by-step explanation:
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