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Nitella [24]
2 years ago
15

What are compatible numbers for 12 and 21

Mathematics
1 answer:
Leni [432]2 years ago
6 0
Compatible number is 33
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Write the equation of a square root function that has the following graph.
Anastaziya [24]

9514 1404 393

Answer:

  g(x) = √(x -5) +7

Step-by-step explanation:

To translate the graph of f(x) by h units horizontally and k units vertically, the function is transformed to ...

  g(x) = f(x -h) +k

To translate f(x) = √x by 5 units horizontally and 7 units vertically, the function is transformed to ...

  g(x) = √(x -5) +7

6 0
2 years ago
YALL so im bored hmu <br> whats 420 - 22 tho
ozzi

Answer:

398

Step-by-step explanation:

5 0
3 years ago
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Does the size of parachute affect the speed and why
Kryger [21]
Yes it does , more mass area = less space
6 0
3 years ago
1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING
iogann1982 [59]

If

y=\displaystyle\sum_{n=0}^\infty a_nx^n

then

y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n

The ODE in terms of these series is

\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0

\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0

\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}

We can solve the recurrence exactly by substitution:

a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0

\implies a_n=\dfrac{(-2)^n}{n!}a_0

So the ODE has solution

y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}

which you may recognize as the power series of the exponential function. Then

\boxed{y(x)=a_0e^{-2x}}

7 0
3 years ago
7,231 divided by 24 is?
Archy [21]
301.2916666667 is your answer.
7 0
3 years ago
Read 2 more answers
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