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2 years ago

Graph the following equations. X=1

Mathematics

2 answers:

kodGreya [7K]2 years ago

6 0

This should be the right answer hope it helps

soldier1979 [14.2K]2 years ago

4 0

Answer:

Vertical line that passes over 1 the x axis. (No y-intercept)

Step-by-step explanation:

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n200080 [17]

Answer:

Step-by-step explanation:

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2 years ago

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Korolek [52]

Answer:

-40

Step-by-step explanation:

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3 years ago

Read 2 more answers

A certain semiconductor device requires a tunneling probability of T = 10-5 for an electron tunneling through a rectangular barr

Goryan [66]

Answer:

Generally the barrier width is $a = 1.9322 *10^{-9} \ m$

Step-by-step explanation:

From the question we are told that

The tunneling probability required is $T = 1 * 10^{-5}$

The barrier height is $V_o = 0.4 eV$

The electron energy is $E = 0.08eV$

Generally the wave number is mathematically represented as

$k = \sqrt{ \frac{2 * m [V_o - E]}{\= h^2} }$

Here m is the mass of the electron with the value $m = 9.11 *10^{-31} \ kg$

h is is know as h-bar and the value is $\= h = 1.054*10^{-34} \ J \cdot s$

$k = \sqrt{ \frac{2 * 9.11 *10^{-31 } [0.4 - 0.04] * 1.6*10^{-19}}{[1.054*10^{-34}^2]} }$

=> $k = 3.073582 *10^{9} \ m^{-1}$

Generally the tunneling probability is mathematically represented as

$T = 16 * \frac{E}{V_o } * [1 - \frac{E}{V_o} ] * e^{-2 * k * a}$

$1.0 *10^{-5} = 16 * \frac{0.04}{0.4 } * [1 - \frac{0.04}{0.4} ] * e^{-2 * 3.0736 *10^{9} * a}$

=> $6.944*10^{-6}= e^{-2 * 3.0736 *10^{9} * a}$

Taking natural log of both sides

$ln[6.944*10^{-6}] = -2 * 3.0736 *10^{9} * a}$

=> $-11.8776 = -2 * 3.0736 *10^{9} * a}$

=> $a = 1.9322 *10^{-9} \ m$

4 0

2 years ago

A. 3/5<br> B. 3/10<br> C. 1/5<br> D. 1/2

Softa [21]

It’s definitely all of the above there all basiclalu the same factor answer it’s just with different numbers

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2 years ago

she can go 6 miles upstream in one and a half hours. going downstream, she goes 24 miles in the same time. determine the speed a

defon

she is going 4mpr. upstream and 16mpr. downstream

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3 years ago