Volume of cone=1/3 times height times pir^2
v=15
r=3
15=1/3 hpi3^2
15=1/3hpi9
15=9/3hpi
15=3hpi
divide 3
5=hpi
h=5/pi
pi=aprox 3.14
5/3.14=1.59
1.59 ft
Answer:
The Olympic sized swimming pool hold 660501.9 gallons of water.
Step-by-step explanation:
Given that:
Water hold by an Olympic sized swimming pool = 2500000 liters
We know that;
1 gallon = 3.785 liters
Therefore,
We will divide the total number of water in liters by 3.785 to find the number of gallons.
Gallons of water in pool = 
Gallons of water in pool =
gallons
Hence,
The Olympic sized swimming pool hold 660501.9 gallons of water.
-10x is the final answer
Hope this helps
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