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pickupchik [31]
3 years ago
10

What is the ratio of stars to hearts?

Mathematics
1 answer:
morpeh [17]3 years ago
8 0
C. 3:2 because that is 6/4 simplified 
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There are 8 and 2 over 3pounds of walnuts in a container, which will be divided equally into containers that hold 1 and 1 over 5
kow [346]

Answer:

  7 4/18

Step-by-step explanation:

  (8 2/3)/(1 1/5) = (26/3)/(6/5) = (26/3)(5/6) = 130/18 = 7 4/18

7 is the integer that goes in the blank

6 0
3 years ago
Find the measure of angle y. Round your answer to the nearest hundredth. (please type the numerical answer only) (6 points)
wolverine [178]

Answer:

35.68°

Step-by-step explanation:

In the picture attached, the triangle is shown.

From sine definition:

sin(y) = opposite/hypotenuse

The leg measuring 7 units is opposite to angle y, and the hypotenuse measures 12 units, therefore:

sin(y) = 7/12

y = arcsin(7/12)

y = 35.68°

4 0
3 years ago
How to solve 3(×-5)-5=23​
USPshnik [31]

Step 1: Simplify both sides of the equation.

3(x−5)−5=23

(3)(x)+(3)(−5)+−5=23(Distribute)

3x+−15+−5=23

(3x)+(−15+−5)=23(Combine Like Terms)

3x+−20=23

3x−20=23

Step 2: Add 20 to both sides.

3x−20+20=23+20

3x=43

Step 3: Divide both sides by 3.

3x /3  =  43 /3

x= 43 /3

4 0
3 years ago
Read 2 more answers
Use a graphing calculator to graph f(x) = x+cos(kx). Use calculus to determine which values of k lead to a function with no loca
nataly862011 [7]

Answer:

Below, you can see the graph of the function:

f(x) = x + cos(k*x)

for different values of k, as follows:

red: k = 1

green: k = 2

orange: k = 0.

Now let's find the values of k such that our function does not have local maxima nor local minima.

First, remember that for a given function f(x), the local maxima or minima points are related to the zeros of the first derivate of f(x).

This means that if:

f'(x0) = 0.

Then x0 is a maxima, minima or an inflection point.

Then if a function is such that the f'(x) ≠ 0 , ∀x, then this function will not have local maxima nor minima.

Now we have:

f(x) = x + cos(k*x)

then:

f'(x) = 1  - k*sin(k*x)

This function will be zero when:

1 = k*sin(k*x)

1/k = sin(k*x)

now, remember that -1 ≤ sin(θ) ≤ 1

then if 1/k is smaller than -1, or larger than 1, we will not have zeros.

And this will happen if -1 < k < 1.

7 0
2 years ago
4x+1 ,3x find the value of x
In-s [12.5K]
I'm assuming that you meant 4x+1=3x?

Subtracting 4x, we get 1=-x.  Multiplying by -1, we get x=-1 as the solution.
6 0
3 years ago
Read 2 more answers
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