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pickupchik [31]
3 years ago
10

What is the ratio of stars to hearts?

Mathematics
1 answer:
morpeh [17]3 years ago
8 0
C. 3:2 because that is 6/4 simplified 
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For brainiest:):):):):):)
eimsori [14]
#1. Step one) we set find what we can multiply by 5 to get 20, so we divide 20 by 5.
20/5 = 4
Step two) we multiply the bottom denominator (8) by 4
8x4=32
Step three) leave the top numerator the same (20) and replace (d) with 32
Answer : 20/32
#2 step one) we divide 14 by 7
14/7 = 2
Step two) divide 10 by 2
10/2=5
Step three) replace z with 5
Answer) 7/5
#3 step one) divide 24 by 8
24/8=3
Step two) divide 21 by 3
21/3 = 7
Step three) replace (x) for (7)
Answer) 7/8
3 0
3 years ago
Someone help me w this problem
kondor19780726 [428]

Answer;

a

Step-by-step explanation:

3 0
3 years ago
Is the binomial x-9 a factor of 4x^3-28^2-36x-27​
Anuta_ua [19.1K]

Answer:

No

Step-by-step explanation:

If (x - 9) is a factor then x = 9 is a root and f(9) = 0

f(x) = 4x³ - 28x² - 36x - 27, hence

f(9) = 4(9)³ - 28(9)² - 36(9) - 27

     = 2916 - 2268 - 324 - 27 = 297

Since f(9) ≠ 0 then (x - 9) is not a factor of f(x)

5 0
3 years ago
Given lines are parallel, find the value of x.<br> Then determine the measure of the angle.
Nadya [2.5K]

Answers:

  • x = 45
  • angle measure = 104 degrees

============================================================

Explanation:

These angles are on alternating sides of the transversal line, and they are exterior of the parallel lines. Therefore, these are alternate exterior angles.

Alternate exterior angles are congruent when we have parallel lines like this.

Set the two expressions equal to each other. Solve for x.

3x-31 = x+59

3x-x = 59+31

2x = 90

x = 90/2

x = 45

Then we can find that:

  • 3x-31 = 3*45-31 = 135-31 = 104
  • x+59 = 45+59 = 104

Both alternate exterior angles are 104 degrees each, which confirms we have the correct x value.

7 0
3 years ago
The equation of the circle whose center is at (3, 7) and whose radius is 6 is a. (x + 3)² + (y + 7)² = 6 b. (x + 3)² + (y + 7)²
kicyunya [14]
\bf \textit{equation of a circle}\\\\ &#10;(x- h)^2+(y- k)^2= r^2&#10;\qquad &#10;center~~(\stackrel{3}{ h},\stackrel{7}{ k})\qquad \qquad &#10;radius=\stackrel{6}{ r}&#10;\\\\\\&#10;(x-3)^2+(y-7)^2=6^2\implies (x-3)^2+(y-7)^2=36
8 0
4 years ago
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