Answer:
#include <iostream>
using namespace std;
void divide(int numerator, int denominator, int *quotient, int *remainder)
{
*quotient = (int)(numerator / denominator);
*remainder = numerator % denominator;
}
int main()
{
int num = 42, den = 5, quotient=0, remainder=0;
divide(num, den, "ient, &remainder);
return 0;
}
Explanation:
The exercise is for "Call by pointers". This technique is particularly useful when a variable needs to be changed by a function. In our case, the quotient and the remainder. The '&' is passing by address. Since the function is calling a pointer. We need to pass an address. This way, the function will alter the value at the address.
To sum up, in case we hadn't used pointers here, the quotient and remainder that we set to '0' would have remained zero because the function would've made copies of them, altered the copies and then DELETED the copies. When we pass by pointer, the computer goes inside the memory and changes it at the address. No new copies are made. And the value of the variable is updated.
Thanks! :)
Its answer is c. hardness
Answer:
In the ISO/IEC 27002 framework, Cryptography describes the use and controls related to encryption, to help an organization implement, maintain, and improve its information security management.
Answer:
a. double-cross
Explanation:
Using the blockchain technology in the case of issuing concert tickets solves the problem with double-cross, which is when someone cheats another person who had trusted in them for some transaction. <em>A great asset with blockchain is the transparency with all the transactions because they are registered and cannot be erased or changed.</em>
<span>The Kshiatriyas family</span>
