Answer:
(5a+b)⋅(5a−b)
Step-by-step explanation:
Changes made to your input should not affect the solution:
(1): "b2" was replaced by "b^2". 1 more similar replacement(s).
STEP
1
:
Equation at the end of step 1
52a2 - b2
STEP
2
:
Trying to factor as a Difference of Squares
2.1 Factoring: 25a2-b2
Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)
Proof : (A+B) • (A-B) =
A2 - AB + BA - B2 =
A2 - AB + AB - B2 =
A2 - B2
Note : AB = BA is the commutative property of multiplication.
Note : - AB + AB equals zero and is therefore eliminated from the expression.
Check : 25 is the square of 5
Check : a2 is the square of a1
Check : b2 is the square of b1
Factorization is : (5a + b) • (5a - b)
You estimate the product by rounding to the nearest 10:
9 becomes 10 and 54 becomes 50
9 x 50 = 450
380
3 hundreds 8 tens
2 hundreds 18 tens
1 hundred 28 tens
0 hundred 38 tens
Answer:
7/3
Explanation:
The slope of the line is equal to the rise/run, or in other words, the number of units the line travels upwards over the number of units the line travels to the right.
We can identify the slope using any two points on the line. Here, we can use the two points that are marked on the picture. The second point is 7 units above the first and 3 units to the right of the first, so the slope of the line is equal to 7/3.
Another way to calculate the slope of the line is the use this formula:
(y2-y1)/(x2-x1)
The first point is at the coordinate (1,-4) and second point is at the coordinate (4,3). When we plug these two coordinates into the equation, we get this:
(y2-y1)/(x2-x1)
->(3-(-4))/(4-1)
When we simply the fraction, we would get 7/3 and that would give us the slope.
I hope this helps!
Complete question:
A circle with radius 3 has a sector with a central angle of 1/9 pi radians
what is the area of the sector?
Answer:
The area of the sector = 
square units
Step-by-step explanation:
To find the area of the sector of a circle, let's use the formula:
Where, A = area
r = radius = 3
Substituting values in the formula, we have:
The area of the sector = square units
