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3 years ago

What are the factors of X squared -100?

Mathematics

2 answers:

Klio2033 [76]3 years ago

7 0

Answer:

(x + 10)(x - 10)

Step-by-step explanation:

x^2 - 100

x(x) - 100

x(x) - 10(10)

(x + 10)(x - 10)

SVEN [57.7K]3 years ago

3 0

Answer:

mmmmmmmkk

Step-by-step explanation:

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The bowl of a circular birdbath has an inside diameter of 18 inches, as shown in the drawing belon.

Step2247 [10]

Answer:

254 square inches

Step-by-step explanation:

A=pi*r^2

A=pi*(d/2)^2

A=3.14*(18/2)^2

A=3.14*(9)^2

A=3.14*81

A=254.34 in^2

So, rounded no the nearest whole, the answer is 254 in^2

Which is option 2 or B

4 0

3 years ago

Is 11/2 and 6/11 equivalent? Plz I need the help☹️

trapecia [35]

For this case we have the following fractions:

$\frac {11} {2}\\\frac {6} {11}$

We must rewrite the fractions, using the same denominator.

We have then:

We multiply the first fraction by 11 in the numerator and denominator:

$\frac {11} {2} \frac {11} {11}$

We multiply the second fraction by 2 in the numerator and denominator:

$\frac {6} {11} \frac {2} {2}$

Rewriting we have:

For the first fraction:

$\frac {121} {22}$

For the second fraction:

$\frac {12} {22}$

We note that:

$\frac {121} {22}> \frac {12} {22}$

Answer:

The fractions are not equivalent:

$\frac {11} {2}> \frac {6} {11}$

5 0

3 years ago

Solve 4x + 5 = x + 26

prohojiy [21]

Answer:

Step-by-step explanation: 7

Subtract 5 on both sides to get 4x = x + 21

then, subtract x from 4x and x is 1, so 3x = 21 then divide by 3 on both sides

8 0

3 years ago

Read 2 more answers

Forty-eight pens are packaged in 4 boxes. How many pens are packaged in 9 boxes?

Monica [59]

48/4= 12 pens per box
12*9 = 108 pens in 9 boxes

6 0

2 years ago

Read 2 more answers

B. Determine the values of a and b so that f is continuous.<br><br> Please help!

wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

$\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to 4a-2b+3 = 4\\\\ \therefore \ \ 4a-2b = 1\\\\$

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

$\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\$

So,

$\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3$

$\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\$

In equation a multiply the by -2 and then add in the equation b:

$\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to -2b = -1\\\\ \to b = \frac{1}{2}$

So, the value of $a \ and \ b= \frac{1}{2}$

4 0

2 years ago