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Alina [70]
3 years ago
5

What is the limit as X is approaching 1?

Mathematics
1 answer:
Paul [167]3 years ago
3 0
2 x^{2} -x-3 = 2 x^{2} +2x-3x-3=2x(x+1)-3(x+1)
=(2x-3)(x+1)

so the limit becomes \lim_{x \to \1} \frac{2x-3}{x-1} = -1/0= -∞
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A right circular cylinder has a volume of 500 cu in. If the base has a radius of 4 in., what's the altitude of the cylinder? Rou
GarryVolchara [31]
<span>Cylinder Volume   =   </span><span>π <span>• r² • height
height = </span></span><span>Cylinder Volume / (PI * radius^2)
</span><span>height = 500 cubic inches / 3.14159 * 16
</span><span><span><span>height = 9.9471839432 </span> </span> </span>
<span>height = 9.95 (rounded)

</span>


4 0
3 years ago
Sam can rent a canoe for $3 an hour. If he rents the canoe, he would also have to pay $15 for a non-refundable deposit. He has $
Nikitich [7]
So, We Need To Write An Equation. Lets Make Some Variables.
Max Amount He Can Spend: X
Max Amount Of Hours: H
Cost Per hour: P
Deposit : D
So, Lets Start.
We Can Write:
H = (X - D) / P
Now, Just Plug In The Known Values.
H = (30 - 15) / 3
That Is Our Equation.

Now, Just For Fun, I Will Solve It.
So, We Need To Simplify.
30 - 15 = 15.
So, We Have:
H = 15/3
So, We Know:
15/3 = 5.
So, We Can Substitute 5 for 15/3.
We Get:
H = 5
So, He Can Canoe For 5 Hours.  
8 0
3 years ago
Lacey and richens decide to connect their two machines so that lacey’s output becomes richens ‘ input. If 3 is the initial, what
motikmotik

Answer:

Step-by-step explanation:

5 0
2 years ago
A spinner with 9 equal sections is numbered 1 through 9. The probability of spinning a 3 is 19 . What is the probability of not
ale4655 [162]
I agree with 18/19 for the answer.
8 0
3 years ago
If thewronskian w of f and g is 3e4t,and if f(t) = e2t,find g(t).
ehidna [41]
W(f(x),g(x))=\begin{vmatrix}f(x)&g(x)\\f'(x)&g'(x)\end{vmatrix}=f(x)g'(x)-g(x)f'(x)

We have f(t)=e^{2t}\implies f'(t)=2e^{2t}, so

W(f(t),g(t))=e^{2t}g'(t)-2e^{2t}g(t)=3e^{4t}
\implies e^{-2t}g'(t)-2e^{-2t}g(t)=3
\implies\dfrac{\mathrm d}{\mathrm dt}[e^{-2t}g(t)]=3
\implies e^{-2t}g(t)=\displaystyle\int3\,\mathrm dt
\implies e^{-2t}g(t)=3t+C
\implies g(t)=3te^{2t}+Ce^{2t}

where C is any arbitrary constant.
8 0
3 years ago
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