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2 years ago

6

Lacey and richens decide to connect their two machines so that lacey’s output becomes richens ‘ input. If 3 is the initial, what

is the final output ?

1 answer:

motikmotik2 years ago

5 0

Answer:

Step-by-step explanation:

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12 2/5 x 3 1/6 pls help me

Maurinko [17]

1. Turn improper
$12 \frac{2}{5} = \frac{62}{5}$
$3 \frac{1}{6} = \frac{19}{6}$
2. set up the problem
$\frac{62}{5} \times \frac{19}{6}$
now multiple across and simplefy

3 0

3 years ago

What is the value of the expression below when x=5?

snow_lady [41]

Answer:

790

Step-by-step explanation:

You put 5 instead of x and you calculat

6*5^3 +8*5= 750+40=790

6 0

3 years ago

Read 2 more answers

Analyze the diagram below and answer the question that follows. 2004-02-03-05-00_files/i0500000.jpg Which of the following is no

meriva

I think the answer is d.8

6 0

3 years ago

Use l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove

steposvetlana [31]

Answer:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}$

Step-by-step explanation:

The limit is:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}$

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

$\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}$

by replacing, and applying repeatedly you obtain:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}$

hence, the limit of the function is -1/14

8 0

3 years ago

Laura has 160 pounds of green beans at her vegetable stand. If she sells 10 pounds of green beans every hour, what is the percen

Mademuasel [1]

Given:

Laura has 160 pounds of green beans at her vegetable stand.

She sells 10 pounds of green beans every hour.

To find:

The percent decrease in green beans after 3 hours.

Solution:

We have,

Beans sold in 1 hour = 10 pounds

So, Beans sold in 3 hours = 30 pounds

Decrease in green beans after 3 hours is 30 pounds.

Now,

$\%\text{Decrease}=\dfrac{\text{Decrease in green beans after 3 hours }}{\text{Initial amount of green beans}}\times 100$

$\%\text{Decrease in green beans after 3 hours}=\dfrac{30}{160}\times 100$

$\%\text{Decrease in green beans after 3 hours}=\dfrac{300}{16}$

$\%\text{Decrease in green beans after 3 hours}=18.75\%$

Therefore, the correct option is A.

7 0

3 years ago