Let's break it down into something more simple:
What's 10 times 10? 100
What's 10 times 10 times 10? 1000
Do you see a pattern? (Cool trick - The number of 10s match the number of 0s in the answer)
We have seven 0s in our answer, so let's check:
10 x 10 x 10 x 10 x 10 x 10 x 10 = 10,000,000
An exponent tells us that we're multiplying the big number by itself however many times the little number in the corner tells us.
So if we multiply 10 by itself 7 times (what we did above), then our answer will be 10 to the power of 7, or 
. This is equal to 10,000,000.
Answer:
49/8 is the value of k
Step-by-step explanation:
We have the system
x = -2y^2 - 3y + 5
x=k
We want to find k such that the system intersects once.
If we substitute the second into the first giving us k=-2y^2-3y+5 we should see we have a quadratic equation in terms of variable y.
This equation has one solution when it's discriminant is 0.
Let's first rewrite the equation in standard form.
Subtracting k on both sides gives
0=-2y^2-3y+5-k
The discriminant can be found by evaluating
b^2-4ac.
Upon comparing 0=-2y^2-3y+5-k to 0=ax^2+bx+c, we see that
a=-2, b=-3, and c=5-k.
So we want to solve the following equation for k:
(-3)^2-4(-2)(5-k)=0
9+8(5-k)=0
Distribute:
9+40-8k=0
49-8k=0
Add 8k on both sides:
49=8k
Divide both sides by 8"
49/8=k
Answer: 28
Step-by-step explanation: 3 1/2 x 4 = 14 x 2 = 28
Answer:
210
Step-by-step explanation:
Here comes the problem from Combination.
We are being asked to find the number of ways out in which 3 students may sit on 7 seats in a row. Please see that in this case the even can not be repeated.
Let us start with the student one. For him all the 7 seats are available to sit. Hence number of ways for him to sit = 7
Let us see the student second. For him there are only 6 seats available to sit as one seat has already been occupied. Hence number of ways for him to sit = 6
Let us see the student third. For him there are only 5 seats available to sit as two seat has already been occupied. Hence number of ways for him to sit = 5
Hence the total number of ways for three students to be seated will be
7 x 6 x 5
=210
<span>1. 6 (378) = 2268 = (189 + 189)6
Properties are:
Addition, you can have 6 + 107 = 113 </span>
<span>Commutative Property by moving: 107 + 6 = 113 </span>
<span>Associative Property by grouping: (3 + 3) + (100 + 7 ) = 113 </span>
<span>Distributive Property by allotting: 2 (3) + 107 = 113 </span>
<span>Multiplication, you can have 6 x 107 = 642 </span>
<span>Commutative Property by moving: 107 x 6 = 642 </span>
<span>Associative Property by grouping: (3 + 3) x (100 + 7 ) = 642 </span>
<span>Distributive Property by allotting: 2(3) x 107 = 642<span>
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