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Lemur [1.5K]
4 years ago
15

What is the subscript present in NaCl?

Chemistry
2 answers:
Marat540 [252]4 years ago
5 0

Answer:

NaCl, or sodium chloride, is commonly known as table salt. ... Subscripts show the ratio of atoms of different elements in the compound. Since there are four hydrogen atoms in the molecule, the subscript 4 follows the symbol for hydrogen.

Explanation:

jonny [76]4 years ago
3 0

Answer:

NaCl or sodium chloride, is commonly known as table salt. ... Subscripts show the ratio of atoms of different elements in the compound. Since there are four hydrogen atoms in the molecule, the subscript 4 follows the symbol for hydrogen.

Explanation:

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Some animals only have ___ cell.
DaniilM [7]
Animal cells have a centrosome and lysosomes, whereas plant cells do not.
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3 years ago
T = 409.5 K, P = 1.50 atm: V = ?L
Molodets [167]

Explanation:

T = 409.5 K, P = 1.50 atm: V = 22.4 L The ideal gas law is: PV = nRT where. P = pressure. V = volume n = number of moles.

7 0
3 years ago
Which gas will effuse at the rate closest At a particular pressure and temperature, nitrogen gas effuses at the rate of 79mLs. U
Contact [7]

Answer : The rate of effusion of sulfur dioxide gas is 52 mL/s.

Solution :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

R\propto \sqrt{\frac{1}{M}}

or,

(\frac{R_1}{R_2})=\sqrt{\frac{M_2}{M_1}}       ..........(1)

where,

R_1 = rate of effusion of nitrogen gas = 79mL/s

R_2 = rate of effusion of sulfur dioxide gas = ?

M_1 = molar mass of nitrogen gas  = 28 g/mole

M_2 = molar mass of sulfur dioxide gas = 64 g/mole

Now put all the given values in the above formula 1, we get:

(\frac{79mL/s}{R_2})=\sqrt{\frac{64g/mole}{28g/mole}}

R_2=52mL/s

Therefore, the rate of effusion of sulfur dioxide gas is 52 mL/s.

4 0
3 years ago
Please answer ASAP!!
Alenkasestr [34]

Answer:

C.0.28 V  

Explanation:

Using the standard cell potential we can find the standard cell potential for a voltaic cell as follows:

The most positive potential is the potential that will be more easily reduced. The other reaction will be the oxidized one. That means for the reactions:

Cu²⁺ + 2e⁻ → Cu E° = 0.52V

Ag⁺ + 1e⁻ → Ag E° = 0.80V

As the Cu will be oxidized:

Cu → Cu²⁺ + 2e⁻

The cell potential is:

E°Cell = E°cathode(reduced) - E°cathode(oxidized)

E°cell = 0.80V - (0.52V)

E°cell = 1.32V

Right answer is:

<h3>C.0.28 V </h3>

<h3 />

4 0
3 years ago
For a theoretical yield of 2.97 g and percent yield of 93.4452%, calculate the actual yield for a chemical reaction. Answer in u
MariettaO [177]

Answer:

2.77532244 grams

Explanation:

Percent yeild=actual/theoretical * 100

Plug in the values

93.4452=actual/2.97 *100

0.934452*2.97=2.77532244

3 0
3 years ago
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