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choli [55]
2 years ago
10

Jesse is riding the bus home from school. He is moving away at 30 miles per hour. From which reference point would this descript

ion be correct? A. Jesse's home B. the driver of the bus C. the school D. another student on the bus
Chemistry
1 answer:
NISA [10]2 years ago
6 0

Answer:

the correct answer is going to be the school

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Ok, got it!!! thank you so much
bekas [8.4K]
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7 0
2 years ago
Please help me I will give a brainleist​
Korvikt [17]
When the dew point temperature and air temperature are equal, the air is said to be saturated. Dew point temperature is NEVER GREATER than the air temperature. Therefore, if the air cools, moisture must be removed from the air and this is accomplished through condensation.
7 0
3 years ago
2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2
Harrizon [31]

It can be found that 337.5 g of AgCl formed from 100 g of silver nitrate and 258.4 g of AgCl from 100 g of CaCl₂.

<u>Explanation:</u>

2AgNO₃ + CaCl₂ → 2 AgCl + Ca(NO₃)₂

We have to find the amount of AgCl formed from 100 g of Silver nitrate by writing the expression.

100 g \text { of } A g N O_{3} \times \frac{2 \text { mol } A g N O_{3}}{169.87 g A g N O_{3}} \times \frac{2 \text { mol } A g C l}{1 \text { mol } A g N O_{3}} \times \frac{143.32 g A g C l}{1 \text { mol } A g C l}

= 337.5 g AgCl

In the same way, we can find the amount of silver chloride produced from 100 g of Calcium chloride.

It can be found as 258.4 g of AgCl produced from 100 g of Calcium chloride.

4 0
3 years ago
Why is graphite used instead of gold or copper wires to conduct electricity in very hot situations such as an industrial kiln?
olga2289 [7]
<span>The strong bonds give graphite high boiling and melting points, while the weak bonds make graphite soft and flexible.</span>
5 0
2 years ago
Read 2 more answers
For the reaction shown, calculate how many grams of each product form when the following amounts of reactant completely react to
stira [4]
This may help you
<span>You need to use some stoichiometry here. The only way to do that is if you're working in moles. Since you're given grams of Al, you can convert that moles by dividing by the molar mass. Then from looking at the coefficients in your equation, you can see that for however many moles of Al react, the same numbers of moles of Fe will be produced, but only half as many moles of Al2O3 will be produced. To go back to grams, multiply the moles of each product that you get by their molar masses!</span>
7 0
3 years ago
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