All categories

3 years ago

What is a hypothesis in a controlled experiment?

2 answers:

4 0

A hypothesis is a tentative, testable statement based on inferences. A controlled experiment is used to test hypothesis. It is designed such that the independent (or manipulated) variable is changed in order to observe its effects on the dependent(or responding) variable.

ser-zykov [4K]3 years ago

3 0

Theory as to what will happen in the experiment. It is essentially an educated guess about what you expect the outcome of the experiment to be.

You might be interested in

What happens at the particle level in a chemical reaction?

mr_godi [17]

Hello,

Here is your answer:

The proper answer to your question is that "the particles will rather speed up or slow down depending on what type reaction".

If you new anymore help feel free to ask me!

Hope this helps!

8 0

3 years ago

Which of the following molecules has the same empirical formula as glucose (C6H1206)

timama [110]

Answer:

ethanoic acid

Explanation:

as it also contains carbon dioxide water and oxygen as glucose

hope it helps you

please mark me as brainlist

4 0

3 years ago

Read 2 more answers

Write the balanced COMPLETE ionic equation for the reaction when aluminum nitrate and sodium hydroxide are mixed in aqueous solu

rjkz [21]

Answer:See explanation

Explanation:

MOLECULAR REACTION EQUATION;

Al(NO3)3(aq) + 3NaOH(aq) --->Al(OH)3(s) +3NaNO3(aq)

complete ionic equation:

Al^3+(aq) + 3NO3^-(aq) + 3Na^+(aq) + 3OH^-(aq) ---->Al(OH)3(s) + 3Na^+(aq) + 3NO3^-(aq)

Net ionic reaction equation;

Al^3+(aq) + 3OH^-(aq) ------> Al(OH)3(s)

8 0

3 years ago

Iron and vanadium both have the BCC crystal structure and V forms a substitutional solid solution in Fe for concentrations up to

Bess [88]

Answer:

Explanation:

To find the concentration; let's first compute the average density and the average atomic weight.

For the average density $\rho_{avg}$ ; we have:

$\rho_{avg} = \dfrac{100}{ \dfrac{C_{Fe} }{\rho_{Fe}} + \dfrac{C_v}{\rho_v} }$

The average atomic weight is:

$A_{avg} = \dfrac{100}{ \dfrac{C_{Fe} }{A_{Fe}} + \dfrac{C_v}{A_v} }$

So; in terms of vanadium, the Concentration of iron is:

$C_{Fe} = 100 - C_v$

From a unit cell volume $V_c$

$V_c = \dfrac{n A_{avc}}{\rho_{avc} N_A}$

where;

$N_A$ = number of Avogadro constant.

SO; replacing $V_c$ with $a^3$ ; $\rho_{avg}$ with $\dfrac{100}{ \dfrac{C_{Fe} }{\rho_{Fe}} + \dfrac{C_v}{\rho_v} }$ ; $A_{avg}$ with $\dfrac{100}{ \dfrac{C_{Fe} }{A_{Fe}} + \dfrac{C_v}{A_v} }$ and

$C_{Fe}$ with $100-C_v$

Then:

$a^3 = \dfrac { n \Big (\dfrac{100}{[(100-C_v)/A_{Fe} ] + [C_v/A_v]} \Big) } {N_A\Big (\dfrac{100}{[(100-C_v)/\rho_{Fe} ] + [C_v/\rho_v]} \Big) }$

$a^3 = \dfrac { n \Big (\dfrac{100 \times A_{Fe} \times A_v}{[(100-C_v)A_{v} ] + [C_v/A_Fe]} \Big) } {N_A \Big (\dfrac{100 \times \rho_{Fe} \times \rho_v }{[(100-C_v)/\rho_{v} ] + [C_v \rho_{Fe}]} \Big) }$

$a^3 = \dfrac { n \Big (\dfrac{100 \times A_{Fe} \times A_v}{[(100A_{v}-C_vA_{v}) ] + [C_vA_Fe]} \Big) } {N_A \Big (\dfrac{100 \times \rho_{Fe} \times \rho_v }{[(100\rho_{v} - C_v \rho_{v}) ] + [C_v \rho_{Fe}]} \Big) }$

Replacing the values; we have:

$(0.289 \times 10^{-7} \ cm)^3 = \dfrac{2 \ atoms/unit \ cell}{6.023 \times 10^{23}} \dfrac{ \dfrac{100 (50.94 \g/mol) (55.84(g/mol)} { 100(50.94 \ g/mol) - C_v(50.94 \ g/mol) + C_v (55.84 \ g/mol) } }{ \dfrac{100 (7.84 \ g/cm^3) (6.0 \ g/cm^3 } { 100(6.0 \ g/cm^3) - C_v(6.0 \ g/cm^3) + C_v (7.84 \ g/cm^3) } }$

$2.41 \times 10^{-23} = \dfrac{2}{6.023 \times 10^{23} } \dfrac{ \dfrac{100 *50*55.84}{100*50.94 -50.94 C_v +55.84 C_v} }{\dfrac{100 * 7.84 *6}{600-6C_v +7.84 C_v} }$

$2.41 \times 10^{-23} (\dfrac{4704}{600+1.84 C_v})=3.2 \times 10^{-24} ( \dfrac{284448.96}{5094 +4.9 C_v})$

$\mathbf{C_v = 9.1 \ wt\%}$

4 0

3 years ago

What di you think you would see happen in the bucket as ice comes into contact with high kinetic energy molecules?

cricket20 [7]

Answer:The ice will melt

Explanation:

5 0

3 years ago