All categories

3 years ago

Please help I don’t understand it

Mathematics

1 answer:

dybincka [34]3 years ago

7 0

C= number of crickets
g= number of grasshoppers= twice number of crickets= 2c
T= total number of both= 561

If you add the number of crickets and the number if grasshoppers, you'll get a total of 561.

c + g= T
c + g= 561

Now we also know that grasshoppers are 2c (twice the crickets). Substitute 2c for g in the equation to solve for c.

c + g= 561
c + 2c= 561
combine like terms
3c= 561
divide both sides by 3
c= 187 crickets

Substitute number of crickets back in equation to find g.

c + g= 561
187 + g= 561
subtract 187 from both sides
g= 374 grasshoppers

CHECK:
Since grasshoppers are twice the number of crickets, then multiplying the number of crickets by two should equal the number of grasshoppers.
187 * 2= 374
374= 374

ANSWER: 187 crickets and 374 grasshoppers

Hope this helps! :)

You might be interested in

I need help i dont understand this,and j have and i have a big test coming up please help thanks

levacccp [35]

Since both of the angles are supplementary, you'd set the expressions up into an equation equal to 180(degrees).
So, your equation should look like:
                       22x + 4 + 35x + 5 = 180.
Next, you combine your like terms so that your next move will look like:
                       57x + 9 = 180.
Then you'd follow the subtraction and division property, so your next moves will look as the following:
                       57x + 9 - 9 = 180 - 9 equals 171
                       57x / 57 = 171 / 57 equals 3
So, finally, your answer is: x = 3.

7 0

3 years ago

in a class of 37 students,the number of students who like martial art only is double than the number of students who like athlet

yulyashka [42]

Answer:

number of students who like Athletics only = x = 10 students

number of students who like marshal arts only = 2x = 20 students

Step-by-step explanation:

In a class of 37 students, the number of students who like marshal arts only is

double than the number of students who like athletics only. If 3 students like both

and 4 like none of the games, find out how many students like:

i. Marshal arts

ii. Athletics

Total students in the class = 37

number of students who like Athletics only = x

number of students who like marshal arts only = 2x

Number of students who like both = 3

Number of students who like none = 4

Total = athletics + marshal art + both + none

37 = x + 2x + 3 + 4

37 = 3x + 7

37 - 7 = 3x

30 = 3x

x = 30/3

x = 10

number of students who like Athletics only = x = 10 students

number of students who like marshal arts only = 2x

= 2(10)

= 20 students

5 0

3 years ago

In a square, a diagonal measures 15 inches. Find the perimeter of the square

attashe74 [19]

Check the picture below.

4 0

3 years ago

If KL = LM and KJ = JM, find m ∠KJL<br><br> please, i really need your help!

umka2103 [35]

The triangles are congruent by SAS, so the two angles with 7x and 3x+16 are equal. So

7x=3x+16
4x=16
x=4

So KJL=7(4)=28.

3 0

3 years ago

Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

3 years ago