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amm1812
2 years ago
5

What is the area of the following circle?

Mathematics
1 answer:
Aleks04 [339]2 years ago
4 0
A=pi x r^2

Therefore the area is 25pi
You might be interested in
If
Anna11 [10]
Answer: -104

Explanation: x=-9 y=2
2(y-3xy)
=2(2-3(-9)(2))
=4-2(3(-18))
=4-108
=-104

Hope it helped

4 0
1 year ago
Multiply. use the gcf. 3/4 7/9
oee [108]

21/36.

All you have to do is multiply numerators by numerators and denominators by denominators. Simplify if needed

Please consider marking branliest if this helped

7 0
3 years ago
Simplify the following expression. √14 / √18
3241004551 [841]
<span>√7/3 is the answer

hope this helps</span>
3 0
2 years ago
4/5+ unknown number =14/15
prohojiy [21]

Answer:

The unknown number is 2/15.

Step-by-step explanation:

4/5+x=14/15

x=14/15-4/5

x=14/15-12/15

x=2/15

5 0
2 years ago
Read 2 more answers
- Write a recursive formula to represent the sequence below.<br> (3,7, 11, 15, 19,23,27,31,35, ...)
NemiM [27]

<em><u>The recursive formula to find nth term of sequence is:</u></em>

a_n = 4n - 1 \text{ where } n \geq 1 and n  = 1, 2, 3, ....

<em><u>Solution:</u></em>

Given a sequence is:

3, 7, 11, 15, 19, 23, 27, 31, 35

<em><u>Let us find the difference between terms</u></em>

7 - 3 = 4

11 - 7 = 4

15 - 11 = 4

19 - 15 = 4

23 - 19 = 4

27 - 23 = 4

31 - 27 = 4

35 - 31 = 4

Thus the difference between terms is constant

Thus the given sequence is arithmetic sequence

An arithmetic sequence is a sequence of numbers such that the difference of any two successive members of the sequence is a constant

<em><u>The nth term of arithmetic sequence is given by:</u></em>

a_n =a_1+(n-1)d

a_n = the nᵗʰ term in the sequence

a_1 = the first term in the sequence

d = the common difference between terms

Here in the given sequence

d = 4

a_1=3

Substitute in above formula,

a_n = 3 + (n-1)(4)\\\\a_n = 3 + 4n - 4\\\\a_n = 4n - 1

<em><u>Thus the recursive formula to find nth term of sequence is:</u></em>

a_n = 4n - 1 \text{ where } n \geq 1 and n = 1, 2, 3, ......

8 0
2 years ago
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