Question

What pressure does a 130-pound women exert on the floor when she

Answer 1

Answer:

Pressure, $P=4.56\times 10^6\ Pa$

Step-by-step explanation:

Given that,

Force exerted by woman on the floor, F = 130 pounds = 578.26 N

Radius of her heels, r = 0.25 inches = 0.00635 m

We need to find the pressure exerted by woman on the floor. We know that pressure exerted by an object is equal to the force acting per unit area. So,

$P=\dfrac{F}{A}\\\\P=\dfrac{578.26 \ N}{\pi (0.00635\ m)^2}\\\\P=4.56\times 10^6\ Pa$

So, the pressure exerted by the woman on the floor is $4.56\times 10^6\ Pa$.