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Anettt [7]
3 years ago
8

If point D' is the image of D(-2,1) under a reflection across the x-axis. What are the coordinates of D'?

Mathematics
2 answers:
kolbaska11 [484]3 years ago
6 0
The answer is (-2,-1)
konstantin123 [22]3 years ago
4 0

Answer:

(-2, -1)

Step-by-step explanation:

When reflecting across the x-axis, the x coordinate remains the same, but the y-coordinate turns to its opposite. So to get D from D', keep -2, and make 1 a -1.

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Trava [24]

Answer:

The center is the point (3,1) and the radius is 3 units

Step-by-step explanation:

we know that

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we have

x^{2}+y^{2}-6x-2y+1=0

Convert to standard form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(x^{2}-6x)+(y^{2}-2y)=-1

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

(x^{2}-6x+9)+(y^{2}-2y+1)=-1+9+1

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4 0
4 years ago
NM=x-6 , ML=9,LK =2x-19, NK=23 <br> Solve for X
ZanzabumX [31]
X=13, Subtract 9, And add 6 and 19 To both sides. then Divide by three
4 0
4 years ago
A factory can work its employees no more than 6 days a week, and no less than 2 days per
Molodets [167]

Answer:

Step-by-step explanation:

Answer: A.) 2 <= X <= 6

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Step-by-step explanation:

Given that a factory can work its employees no more than 6 days a week, that is, less than or equal to 6 days a week

And also, no less than 2 days per week. That is, greater than or equal to 2 day a week.

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5 days = 6 × 6.5 = 39 hours

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attashe74 [19]

Answer:

Step-by-step explanation:

2

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12 & 35 Third side is hypotenuse = 37
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