Answer:

Step-by-step explanation:
Considering the expression

Lets determine the expansion of the expression




Expanding summation








as





so equation becomes


Therefore,
Step-by-step explanation:
Let the number be x.
<u>1</u><u> </u> =8 + x
6
6×<u>1</u>=6×8+6×x
6
1=48+6x
1-48=6x
<u>-</u><u>4</u><u>7</u>=<u>6</u><u>x</u>
6. 6 x = -7 <u>5</u>
6
x is equal to minus seven whole number five divided by six.
Step-by-step explanation:
Let the width be x feet.
Therefore, length = 2x - 10
Perimeter of rectangle = 52

Assume each square is 1 unit.
The base of the large triangle is 6 units and the base of the smaller triangle is 3 units.
The scale factor is 1/2