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vaieri [72.5K]
3 years ago
15

The ones digit of a two-digit number is 4 more than the tens digit. Find the number, if the sum of that number and the number re

versed is 110.
Mathematics
1 answer:
valkas [14]3 years ago
3 0

Answer:

37

Step-by-step explanation:

Let the answer be represented by xy  where x is the tens digit and y is the ones digit.

The ones digit of a two-digit number is 4 more than the tens digit.

y = x+4

the sum of that number and the number reversed is 110

xy+yx = 110

Lets rewrite this vertically

 x y

 y x

------

1 1 0


We can replace y with x + 4  I will put the 4's in a separate row up top for ease of writing

 4 4

 x x

 x x

------

1 1 0


Taking the one's column, we get

2x +4 = 0  and I will assume there is a carry of 10

so rewriting

2x+4 = 10

Subtract 4 from each side

2x+4 -4 = 10-4

2x =6

Divide each side by 2

2x/2 = 6/2

x=3

We still need to find y

y = x+4

Substituting in x

y = 3+7

y =7

The number is xy

37



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