The magnitude of the magnetic field in the central area inside the solenoid, in T is 0.0267 T
<h3>Magnetic field inside solenoid</h3>
The magnetic field inside the central area of the solenoid is given by B = μ₀ni where
- μ₀ = permeability of free space = 4π × 10⁻⁷ Tm/A,
- n = number of turns per unit length = 3,170 turns/m and
- i = current in solenoid = 6.7 A
Since B = μ₀ni
Substituting the values of the variables into the equation, we have
B = μ₀ni
B = 4π × 10⁻⁷ Tm/A × 3,170 turns/m × 6.7 A
B = 4π × 10⁻⁷ Tm/A × 21239 A-turns/m
B = 84956π × 10⁻⁷ T
B = 266897.15 × 10⁻⁷ T
B = 0.026689715 T
B ≅ 0.0267 T
So, the magnitude of the magnetic field in the central area inside the solenoid, in T is 0.0267 T
Learn more about magnetic field inside a solenoid here:
brainly.com/question/25562052
Answer:
Step-by-step explanation: what are the dimensions
Find out which fraction is bigger. 1/3 or 1/2
1/3 = 2/6 and 1/2=3/6.
3 > 2
so 1/2>1/3
Hope this helps.
What is the question? Do they want us to find a’,b’, and c’??
