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zhannawk [14.2K]
3 years ago
5

Which of the following combinations of elements is most likely to produce covalent bonds?

Physics
2 answers:
bearhunter [10]3 years ago
7 0

Answer:

b

Explanation:

Dennis_Churaev [7]3 years ago
6 0

Answer:

b

Explanation:

because it is bond made between two metals

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Choloroplast definition ???
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<span>a plastid that contains chlorophyll and in which photosynthesis takes place.</span>
3 0
4 years ago
Read 2 more answers
A pendulum of length 130.0 cm has a period of oscillation, T₁. The bob is pulled and released to move in a horizontal circle of
Anastasy [175]

The ratio of T1 : T2 is 1.6

<h3>What is Simple Harmonic Motion ?</h3>

SHM is the periodic motion of a particle along a line such that the acceleration of the body is directed toward a fixed point and proportional to its displacement.

Given that a pendulum of length 130.0 cm has a period of oscillation, T₁.

Then, The period T₁ = 2\pi\sqrt{\frac{l}{g} }

T₁ = 2 x 3.142 \sqrt{\frac{1.3}{10} }

T₁ = 6.284 x 0.36

T₁ = 2.266

But if T = 0

then, mv^{2} /r = mg

the m will cancel out

Then v = \sqrt{rg}

where r = 50/100 = 0.5m

Substitute into the formula

v = \sqrt{ 0.5 * 10}

v = 2.24 m/s

Also, given that the bob is pulled and released to move in a horizontal circle of radius 50.0 cm and the period of rotation is T2,

w = 2\pif

w = 2\pi/T

but v = wr

w = v/r

Therefore,

v/r = 2\pi/T

Substitute all the parameters into the formula

2.24/0.5 = (2 x 3.1423) /T

T = 6.284/4.472

T = 1.405 = T_{2}

The ratio T₁: T2 will be 2.266/1.405

The ratio is 1.6

Learn more about Simple Harmonic Motion here: brainly.com/question/24646514

#SPJ1

4 0
2 years ago
A 2000 kg test car travels around a circular track with a radius of 100 m. If the
Anarel [89]

Answer:

V=0.38 m/s

Explanation:

ac=3 m/s^2

m=2000kg

r=100m

ac=mv^2/r

Solve for v^2

3=2000(v^2)/100

3=20v^2

3/20=.15

sqrt of .15= 0.38 m/s

V=0.38 m/s

6 0
3 years ago
The electrical and magnetic components of an EM wave are _________________.
Ira Lisetskai [31]
Parrallel to each other
3 0
3 years ago
The average marathon runner can complete the 42.2-km distance of the marathon in 3 h and 30 min. If the runner's mass is 85 kg,
Semenov [28]

Answer:

the runner's average kinetic energy during the run is 476.96 J.

Explanation:

Given;

mass of the runner, m = 85 kg

distance covered by the runner, d = 42.2 km = 42,200 m

time to complete the race, t = 3 hours 30 mins = (3 x 3600s) + (30 x 60s)

                                                                               = 12,600 s

The speed of the runner, v = d/t

                                          v = 42,200 / 12,600

                                          v = 3.35 m/s

The runner's average kinetic energy during the run is calculated as;

K.E = ¹/₂mv²

K.E = ¹/₂ × 85 × (3.35)²

K.E = 476.96 J

Therefore, the runner's average kinetic energy during the run is 476.96 J.

5 0
3 years ago
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