Answer:
The total time is
.
Explanation:
Given:
The distance between Galactic Capitol and Earth is, 
The speed of light is, 
The time taken by the message to reach and come back to Earth is given by

In addition they take 1 year to decide to reply.
Thus, the total time is
.
Answer:
In which direction does the current in circuit A flow?
counterclockwise
<h2>What is the power dissipated by the resistor of resistance R2 for circuit A, given that E=10 V, R1=300ohms, and R2=5000ohms?
</h2><h2>Calculate the power to two significant figures.</h2><h2>0.064W</h2><h2 /><h2>For what ratio of R1 and R2 would power dissipated by the resistor of resistance R2 be the same for circuit A and circuit B?</h2><h2>R1/R2 =
1
</h2><h2 /><h2>Under which of the following conditions would power dissipated by the resistance R2 in circuit A be bigger than that of circuit B?
</h2><h2>Some answer choices overlap; choose the most restrictive answer.</h2><h2>R2>R1</h2><h2>
</h2>
Explanation:
<h3>
Answer:</h3>
800 meters
<h3>
Explanation;</h3>
<u>We are given;</u>
- Speed as 40 m/s
- Time as 20 seconds
We are required to determine the distance traveled
- Speed refers to the rate of change in distance.
- It is given by;
Speed = Distance ÷ time
Rearranging the formula;
Distance = speed × time
In this case;
Distance = 40 m/s × 20 sec
= 800 meters
Thus, the distance traveled by the car is 800 m
Answer:
ive answered this
Explanation:
please check your previose question
Answer: The question has some details missing. here is the complete question ; Point charge 1.5 μC is located at x = 0, y = 0.30 m, point charge -1.5 μC is located at x = 0 y = -0.30m. What are (a)the magnitude and (b)direction of the total electric force that these charges exert on a third point charge Q = 5.0 μC at x = 0.40 m, y = 0
Explanation:
- a) First of all find the distance between the two charges;
- x = 0, y = 0.30 and x = 0.40 m, y = 0
hence, the force F = 2Kq1q2cosθ /r²...............equation 1
but cosθ = y/r = 0.3/0.5
cosθ = 0.6
plugging back to equation 1;
F = 2 x 9 x 10^9 x 1.5 x 10^-6 x 5 x 10^-6 /0.5^2
F = 540 x 10^-3
Magnitude of Force = 0.54N
b) Direction is at angle 90