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likoan [24]
3 years ago
10

A flagpole is 6.8m tall. A cable is attached from ground to the top of the pole such that it makes a 66 degree angle with the po

le. How long is the cable? How far from the pole is the cable attached to the ground? If the cable is attached 4.2m closer to the pole, what is the new angle between pole and cable?
Physics
1 answer:
soldier1979 [14.2K]3 years ago
3 0

Answer:

Length of cable = 16.7 m

Distance from ground = 15.4

New angle between pole and cable = 58.5 degrees

Explanation:

The flagpole forms a right-angled triangle with the cable and the ground.

Let the adjacent side be the flagpole, the hypotenuse be the cable and the ground be the opposite side.

hypotenuse = h

adjacent = 6.8 m

distance from ground = d

angle = 66.0

cos 66 = 6.8/h

h = 6.8/cos 66

h = 16.7 m

tan 66 = d /6.8

d = 6.8 * tan 66

d = 15.3 m

If the cable is brought 4.2 m closer to the pole, new distance = 15.3 - 4.2 = 11.1 m

let new angle be x

tan x = 11.1/6.8

x = tan⁻¹ (11.1/6.8)

x = 58.5 degrees

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A truck is carrying a refrigerator as shown in the figure. The height of the refrigerator is 158.0 cm, the width is 60.0 cm. The
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The maximum acceleration the truck can have so that the refrigerator does not tip over is 4.15 m/s².

<h3>What will be the maximum acceleration of the truck to avoid tipping over?</h3>

The maximum acceleration is obtained by taking clockwise moments about the tipping point of rotation.

Clockwise moment = Anticlockwise moment

Ft * 1.58 m = F * 0.67 m

where

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m * a * 1.58 = m * 9.81 * 0.67

a = 4.15 m/s²

The maximum acceleration the truck can have so that the refrigerator does not tip over is 4.15 m/s².

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2 years ago
How much tension must a rope withstand if it is used to accelerate 70.0 skier behind a boat at 1.50m/s^2?
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3 years ago
The specific heat of a certain type of metal is 0.128 J/(g⋅∘C).0.128 J/(g⋅∘C). What is the final temperature if 305 J305 J of he
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Answer:

45.3°C

Explanation:

Heat gained = mass × specific heat × increase in temperature

q = mC (T − T₀)

Given C = 0.128 J/g/°C, m = 94.0 g, q = 305 J, and T₀ = 20.0°C:

305 J = (94.0 g) (0.128 J/g/°C) (T − 20.0°C)

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6 0
3 years ago
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kramer

Answer:

60.2 J

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3 years ago
Read 2 more answers
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