All categories

3 years ago

In an endothermic reaction would energy be considered a reactant or a product?

Chemistry

1 answer:

timurjin [86]3 years ago

4 0

Answer:

In an endothermic reaction, the products have more stored chemical energy than the reactants. In an exothermic reaction, the opposite is true. The products have less stored chemical energy than the reactants. The excess energy in the reactants is released to the surroundings

You might be interested in

Which of the following has to remain constant to allow you to use the combined gas law for calculations?

Mazyrski [523]

Answer:

Amount of gas

Explanation:

The combined gas law has to do with pressure, volume, and temperature. All of them can be a variable that you have to solve for. However, amount of gas is not a variable you can solve for, which means it must remain constant.

4 0

3 years ago

When coke burns in air then evolved gas is

Arturiano [62]

Answer:

Explanation:

Carbon (coke) burns in air to form carbon dioxide gas.

(i) C(s) + O2 ↑= CO2 ↑

7 0

3 years ago

A student wants to remove the salt from a mixture of sand and salt in order to get only pure sand. He adds water to the mixture.

raketka [301]

Answer:

Here is one way: Add water to the mixture. Only the sugar dissolves. This is a physical change.

Explanation:

The sugar would dissolve in water. You could then pour off the solution and wash the remaining sand with a bit more water. Heat the water to evaporate it from the sugar, and the two are separated.

5 0

3 years ago

Read 2 more answers

While exploring on your grandfathers farm, you find a layer of charcoal that might represent a campfire built by Native American

Ierofanga [76]

Carbon Dating would tell you the age of the charcoal

8 0

3 years ago

13. A mixture of MgCO3 and MgCO3.3H2O has a mass of 3.883 g. After heating to drive off all the water the mass is 2.927 g. What

rjkz [21]

Answer:

63.05% of MgCO3.3H2O by mass

Explanation:

of MgCO3.3H2O in the mixture?

The difference in masses after heating the mixture = Mass of water. With the mass of water we can find its moles and the moles and mass of MgCO3.3H2O to find the mass percent as follows:

Mass water:

3.883g - 2.927g = 0.956g water

Moles water -18.01g/mol-

0.956g water * (1mol/18.01g) = 0.05308 moles H2O.

Moles MgCO3.3H2O:

0.05308 moles H2O * (1mol MgCO3.3H2O / 3mol H2O) =

0.01769 moles MgCO3.3H2O

Mass MgCO3.3H2O -Molar mass: 138.3597g/mol-

0.01769 moles MgCO3.3H2O * (138.3597g/mol) = 2.448g MgCO3.3H2O

Mass percent:

2.448g MgCO3.3H2O / 3.883g Mixture * 100 =

6 0

3 years ago