The formal name is a thunder cloud
Answer:
The heat needed to warm 406.0 mg of cyclohexane from 33.5°C to 38.9°C is 209.22 Joules
Explanation:
Where:
Q = heat absorbed or heat lost
c = specific heat of substance
m = Mass of the substance
ΔT = change in temperature of the substance
We have mass of cyclohexane = m = 406.0 mg = 0.4060 g
( 1 mg =0.001 g)
Specific heat of cyclohexane = c = 1.85 J/g°CK
ΔT = 38.9°C - 33.5°C = 5.4°C =5.4+273.15 K = 278.55 K
Heat absorbed by the cyclohexane :
The heat needed to warm 406.0 mg of cyclohexane from 33.5°C to 38.9°C is 209.22 Joules
The mass of the element is equal to the summation of the mass of the isotopes multiplied by the percent abundance of the isotope. Isotopes differ in the number of neutrons but the number of protons remains the same. Hence in this problem, the answer is 85.47 g/mol
Answer:
The solution is neither acidic or basic. An acid is a substance that donates hydrogen ions. ... Because the base "soaks up" hydrogen ions, the result is a solution with more hydroxide ions than hydrogen ions. This kind of solution is alkaline. Acidity and alkalinity are measured with a logarithmic scale called pH.
Explanation:
Answer is: 153.52 grams of hypobromous acid <span>must be added.
</span>Chemical dissociation: HBrO ⇄ H⁺ + BrO⁻.
pH = 4.25.
pH = -log[H⁺].
[H⁺] = 10∧(-pH).
[H⁺] = 10∧(-4.25).
[H⁺] = [BrO⁻] = 5.62·10⁻⁵ M.
Ka = [H⁺] · [BrO⁻] / [HBrO].
2.00·10⁻⁹ = (5.62·10⁻⁵ M)² / [HBrO].
[HBrO] = 3.16·10⁻⁹ M² / 2.00·10⁻⁹.
[HBrO] = 1.58 M.
m(HBrO) = n(HBrO) · M(HBrO).
m(HBrO) = 1.58 mol · 96.91 g/mol.
m(HBrO) = 153.52 g.
