I believe that the answer is C
Answer:
well it might be 1.)Cadmium Fluoride CdF2 150.4078
2.)Cadmium(II) Perfluorate Cd(FO4) 2278.403
3.)Cadmium Ferrocyanide Cd2Fe(CN) 6436.7714
Explanation:
O2 isn't necessary for rusting, but some source of oxygen is required. Rust is just another name for iron oxide, and without oxygen there can't be oxide.
Hope this helps,
Davinia.
Use the equation d=m/v
your mass or "m" is 78 g
your volume or "v" is 60mL
if you plug those values into the equation it will look like this:
d=78/60
d=1.3g/mL should be what you come up with