Ka is the equilibrium constant for the ionization for a reaction. It is calculated as follows
ka is equal to (H3o ions)(A-) divided by (HA)
2.00x106i s equal to 0.153x0.153 divided by ( HA)
(2.00x106)HA is equal to 0.023409
HA concentration is therefore equal to 0.023409/2.00x106 which is 1.104x10^-4moles/litre
Answer:
force = 3000N
mass= 20 kg
now
F= ma
3000= 20×a
3000÷20=a
a=15
F= ma by newtons second law of motion
In osmosis, water moves from areas of low concentration of solute to areas of high concentration of solute.
When carbon is burned in air carbon iv oxide gas is formed.
C (s) + O2 (g) = CO2(g) ΔH = - 393.5 kj/mol
The enthalpy change of the reaction is -393.5 j/mol which means that when one mole of carbon is completely burnt in air then 393.5 j of energy is evolved.
Thus, 1 mole = -393.5 j , then for 480 kj
= 480 × 1/393.5
= 1.2198 moles
1 mole of carbon iv oxide is equal to 44 g
thus, 1.2198 moles will be 1.2198 × 44 = 53.6712 g of CO2
Reactants are what is changed in the chemical reaction. They go before the arrow when you wrote the equation. Products are what is formed when the chemical reaction occurs. Products always contain the same elements as the reactants, but they might be rearranged because of the reaction. In this picture, you can see that the reactants go before the arrow, and the products go after.
