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Sergio [31]
3 years ago
15

How do you know when there are no solutions to a system of equations?

Mathematics
1 answer:
Allushta [10]3 years ago
4 0
No solution
========
The lines are parallel
eg
y = 2x + 3; y = 2x + 5

Infinite solutions
============
When one equation reduces to the second one.
2y = 10x + 6
y = 5x + 3 When you divide the first one by 2, you get the second one.
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Calculate the perimeter of a square length of whose side is 40cm​
Verizon [17]

Answer:

160 cm

Step-by-step explanation:

a square has 4 equal sides. if one of the sides is 40 cm, then all of the other sides are 40 cm as well. to get a perimeter, you add up the lengths of all the sides. if there are 4 sides of 40 cm, you multiply 40 by 4 to get 160, finally add the unit to get 160 cm.

8 0
3 years ago
What is the value of k? <br> -k+78=98-20
Jlenok [28]

Answer:

k=0

Step-by-step explanation:

6 0
3 years ago
mark purchased a new motorcycle for $23,000. F the value of the motorcycle decreases by 151 each year, what will it be worth in
HACTEHA [7]
151 * 5 = 755
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It'll be worth $22,245 in 5 years.
4 0
3 years ago
PLEASE HELP!! WILL GIVE BRAINLIEST!!
Anestetic [448]
Area of part 1:A1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2Area of part 2:A2=length*width=(8+2)*1=10 ft2Area of part 3:A3=length*width=8*2=16 ft2
Total shaded area : A1+A2+A3=41 ft2Total area of the reactangle : A=16*8=128 ft2Total area of the nonshaded region : 128-41=87 ft2

8 0
4 years ago
A person drinks 1 pint of milk a day. At this rate how many gallons will a person drink in a leap year (366 days)?
Diano4ka-milaya [45]
OK. SO first you need to know how many pints are in a gallon.  ( one gallon = 8 quarts ) 

One day = one pint. So we want to find what 366 days equals. 1*366=366 pints in 366 days. We now have 366 pints. We need to convert that to gallons. One gallon equals 8 quarts, so we divide 366 by 8. 366/8= 45.75

So in one leap year a person drinks 45.75 gallons of milk

If that doesn't make sense, ask and i can re explain. Hope that helped! <span />
3 0
3 years ago
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