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Nimfa-mama [501]

3 years ago

5

Suppose that an individual has a body fat percentage of 18.9% and weighs 128 pounds. How many pounds of his weight is made up of

fat? Round your answer
to the nearest tenth.
1 pounds

1 answer:

Pavel [41]3 years ago

4 0

Answer:

Step-by-step explanation:

128 * 18.9% = 128 * .189 = 24.192 lbs fat

to convert % to decimal divide by 100

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Find the slope (rate of change) for the following table

Nimfa-mama [501]

Answer:

Slope: 0.3

Step-by-step explanation:

divide 3 by 10 then you got your answer

5 0

3 years ago

Which number is prime?<br> 85<br> 49<br> 70<br> 31

Citrus2011 [14]

Answer: 31 is a prime number because only 1 times itself equals 31. no other two factors equal 31 as a product.

Step-by-step explanation:

5 0

3 years ago

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Find the indicated values, where

Rom4ik [11]

Answer:

option (b) is correct.

The value of $g(f(3)-2f(1))$ is 0.

Step-by-step explanation:

Given: $g(t)=t^2-t$ and $f(x)=1+x$

We have to find the value of $g(f(3)-2f(1))$

Consider the given function $f(x)=1+x$

First evaluate value of function f(x) at x = 3 and 1 then substitute it in $g(f(3)-2f(1))$ .

f(3) = 1 + 3 = 4

f(1) = 1 + 1 = 2

Substitute, we get

$g(f(3)-2f(1))=g(4-2(2))$

Solving further , we get,

$g(f(3)-2f(1))=g(4-4)=g(0)$

Now evaluate $g(t)=t^2-t$ at t = 0 , we get,

$g(0)=0^2-0=0-0=0$

Thus, value of $g(f(3)-2f(1))$ is 0.

Thus, option (b) is correct.

4 0

3 years ago

Read 2 more answers

A 3-dimensional shape is made of 36 unit cubes, without any gaps. What is the volume of the shape?

fomenos

Answer:

36 unit

Step-by-step explanation:

The number of unit cubes in the shape = 36 unit cubes

The dimension (volume) of each cubes = 1 unit³

The type of shape = 3-dimensional

The arrangement of the cubes in the shape = Without gaps

The volume of a 3-dimensional shape made of a number of unit cubes without gaps is equal to the sum of the unit cubes

Therefore;

The volume of the 3-dimensional shape that consists of 36 unit cube, V = (1 + 1 + 1 +...+ 1) unit³ = 36 unit³

The volume of the 3-dimensional shap³e, V = 36 unit³

7 0

3 years ago

A certain code is a sequence of 7 digits. What is the probability of generating 7 digits and getting the code consisting of 1, 2

Oksana_A [137]

Answer:

The code has 7 digits:

Here you are asking:

"What is the probability that the code is consisting only of the digits {1, 2, 3, 4, 5, 6, 7}?"

Ok, first we must calculate the number of all the possible codes.

Suppose that each digit is an independent event.

Each one of those events has 10 possible outcomes {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}

And we have 7 of those.

The total number of possible combinations is equal to the product of the number of outcomes for each event, then the total number of possible combinations is:

C = 10^7.

Now let's calculate the number of possible codes if we only use the digits in the restriction.

We can do exactly the same as above, but now in each case, we have 7 possible outcomes for each digit, then in this case the number of possible combinations is:

c = 7^7.

Now the probability of generating at random a code that only uses the digits {1, 2, 3, 4, 5, 6, 7} is equal to the quotient between the number of codes that only use these digits, and the total number of possible codes.

P = c/C = (7^7)/(10^7) = (7/10)^7 = 0.082

4 0

3 years ago