Karl earned scores of 58, 88, 80, and 70 on his first 4 Chemistry tests. What is the minimum score he needs to earn on his fifth
test to ensure that his average score for the 5 tests will be at least 75 ?
2 answers:
Answer:
79
Step-by-step explanation:
(58+88+80+70+ x)/5=75
75*5=296x
375=296x
x=375-296
x=79
Answer: 50
Step-by-step explanation:
First let's set up an equation by calling the score he needs to get, x:
= 75
58 + 88 + 80 + 70 + x = 75 x 5
296 + x = 375
x = 79
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Answer:
45
Step-by-step explanation:
c^2*b
We know that c is 3, and b is 5, so we can substitute them in
3^2*5
Solve the exponent first
9*5
Multiply
45
The answer is n= 3.
Hope this helps.
Answer:
4 different answers
Step-by-step explanation:
1.
[(24/3) + (5*2^2)] = 28
2.
[(3 + 5) * 2^2 )]/24 = 32/24 = 4/3
3.
[(24/3 + 5)*2^2] = 52
4.
[(3 + 5*2^2)/24] = 23/24
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