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I am Lyosha [343]
3 years ago
8

A=2x+6xz a=2x+6xz for x

Mathematics
2 answers:
Dennis_Churaev [7]3 years ago
5 0
So I guess we are solving for x here :)
So here is my work...
a=2x+6xz
Basically I think it would be
a=6xz+2x

WAIT WAIT NO I'M WRONG FORGIVE ME!

It's  x=a/2(1+3z)
juin [17]3 years ago
3 0

Answer:

x = \dfrac{ a}{ 2+ 6z}

Step-by-step explanation:

given,

      a    =  2 x + 6 x z ..........................................(1)

to find the value of x take common from Left hand side of Equation (1)

taking common x

      a    =  ( 2  + 6  z ) x ..........................................(2)

dividing both side by ( 2  + 6  z ) in equation (2) we get

   x = \dfrac{ a}{ 2+ 6z}

hence, the answer is x = \dfrac{ a}{ 2+ 6z}

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What is 27/9 times 198/3?<br><br> Asking for my sis in G5.
choli [55]

Answer:

198

Step-by-step explanation:

27/9 becomes three and then there is no need to divide 198 by three because it is being multiplied by three

3 0
2 years ago
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Dean needs $150 for a miming class. He already has $85 and he can earn the rest by working 13 hours at his job. If h represents
AnnyKZ [126]

Answer:

h=$65/13

Step-by-step explanation:

So he has $85

Now the remaining amount he needs is $65

And in every 13h he produces the $65

So to find his hourly earning is h=$65/13

So the equation is

h = $65/13

3 0
3 years ago
3 X 4 + 4 = ______Immersive Reader (5 Points)
son4ous [18]

Answer:

16

Step-by-step explanation:

8 0
3 years ago
1. Among 806 people asked which is there favorite seat on a plane, 492 chose the window seat, 8 chose the middle seat, and 306 c
prisoha [69]

Answer:

See explanation

Step-by-step explanation:

Among 806 people asked which is there favorite seat on a plane, 492 chose the window seat, 8 chose the middle seat, and 306 chose the aisle seat, then

P(\text{Window seat})=\dfrac{492}{806}=\dfrac{246}{403}\\ \\P(\text{Middle seat})=\dfrac{8}{806}=\dfrac{4}{403}\\ \\P(\text{Aisle seat})=\dfrac{306}{806}=\dfrac{153}{403}

a) One randomly selected person preferes aisle seat with probability

\dfrac{153}{403}

b) Two randomly selected people both prefer aisle seat (with replacement) is

\dfrac{306}{806}\cdot \dfrac{306}{806}=\dfrac{153}{403}\cdot \dfrac{153}{403}=\dfrac{23,409}{162,409}

c) Two randomly selected people both prefer aisle seat (without replacement) is

\dfrac{306}{806}\cdot \dfrac{305}{805}=\dfrac{153}{403}\cdot \dfrac{61}{161}=\dfrac{9,333}{64,883}

8 0
3 years ago
Rich measured the height of a desk to be 80.7 cm. The actual height of the desk is 80 cm. What is Rich's percent error in this c
Hitman42 [59]

Answer:

0.9%

Step-by-step explanation:

We have been given that Rich measured the height of a desk to be 80.7 cm. The actual height of the desk is 80 cm.

We will use percentage error formula to solve our given problem.

\text{Percentage error}=\frac{\text{Experimental value-Actual value }}{\text{Actual actual}}\times 100

\text{Percentage error}=\frac{80.7-80}{80}\times 100

\text{Percentage error}=\frac{0.7}{80}\times 100

\text{Percentage error}=0.00875\times 100

\text{Percentage error}=0.875\approx 0.9

Therefore, Rich's percent error in calculation is 0.9%.

5 0
3 years ago
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