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3 years ago

A=2x+6xz a=2x+6xz for x

2 answers:

5 0

So I guess we are solving for x here :)
So here is my work...
a=2x+6xz
Basically I think it would be
a=6xz+2x

WAIT WAIT NO I'M WRONG FORGIVE ME!

It's x=a/2(1+3z)

juin [17]3 years ago

3 0

Answer:

$x = \dfrac{ a}{ 2+ 6z}$

Step-by-step explanation:

given,

a = 2 x + 6 x z ..........................................(1)

to find the value of x take common from Left hand side of Equation (1)

taking common x

a = ( 2 + 6 z ) x ..........................................(2)

dividing both side by ( 2 + 6 z ) in equation (2) we get

$x = \dfrac{ a}{ 2+ 6z}$

hence, the answer is $x = \dfrac{ a}{ 2+ 6z}$

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El -2,4 es un número entero✨ Gracias!!! ✨✨✨

Marizza181 [45]

Answer:2

Step-by-step explanation:

subtract

3 0

2 years ago

A box contains different colored paper clips. The probability of drawing two red paper clips from the box without replacement is

ivann1987 [24]

Answer: 5/14 which is choice B

================================================

How I got this answer:

Define the following events

A = event of picking a red paper clip on the first selection

B = event of picking a red paper clip on the second drawing

Replacement is not made.

Now onto the probabilities for each

P(A) = 2/5 = 0.4 is given to us as this is simply the probability of picking red on the first try

P(A and B) = probability of both events A and B happeing simultaneously = 1/7

P(B|A) = probability event B occurs, given event A has occured

P(B|A) = probability of selecting red on second selection, given first selection is red (no replacement)

P(B|A) = P(A and B)/P(A)

P(B|A) = (1/7) / (2/5)

P(B|A) = (1/7) * (5/2)

P(B|A) = (1*5)/(7*2)

P(B|A) = 5/14

So if event A happens, then the chances of event B happening is 5/14

------------------

A more concrete example:

If we had 15 paperclips, and 6 of them were red, then

P(A) = (# of red)/(# total) = 6/15 = 2/5

P(B|A) = (# of red left)/(# total left) = (6-1)/(15-1) = 5/14

P(A and B) = P(A)*P(B|A) = (2/5)*(5/14) = 10/70 = 1/7

7 0

3 years ago

Read 2 more answers

HELP

xeze [42]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

To get the echo of a positive integer, we write it twice in a row without a space. For example, the echo of 2022 is 20222022. Is

Lynna [10]

The echo number 20222022202220222022 is the perfect square of 4496890281.

<h3>What echo number is a perfect square</h3>

An echo number has a perfect square if its square root is also a natural number. After some iterations we found that echo number 20222022202220222022 is a perfect square:

$\sqrt{20222022202220222022} = 4496890281$

The echo number 20222022202220222022 is the perfect square of 4496890281. $\blacksquare$

To learn more on natural numbers, we kindly invite to check this verified question: brainly.com/question/17429689

8 0

2 years ago

Can any negative integer be greater than a positive integer explain

Keith_Richards [23]

No, it is impossible. Intuitively, a negative number sits at the left of 0 on the number line, and a positive number sits at the right of 0 on the number line. And a number x is greater than another number y if x sits at the right of y on the number line. So, every positive number is greater than any negative number.

Also, by definition, a positive number is greater than 0, and a negative number is smaller than zero. So, if x is positive and y is negative, you have

$y < 0 < x$

and since the relation of order "<" is transitive, this implies

$y < x$

5 0

2 years ago