Answer:
3000 bags
Step-by-step explanation:
In this case we must apply the formula of the mean, which would be the sum of the values divided by the amount of data is the mean:
m = (a1 + a2 ... an) / n
In this case we know the mean, we must know the 1987 data, therefore:
Let x be the number of bags sold in 1987, replacing in the previous equation:
2100 = (1800 + 1500 + x) / 3
2100 * 3 = 3300 + x
x = 6300 - 3300
x = 3000
Therefore, for the average to be a total of 2100 bags in those 3 years, the amount of bag sold in 1987 must have been 3000 bags
I think the independent variable is the number of people and the dependent is the wait time. I see it as the wait time DEPENDS on how many people are in line. This one is kinda confusing tho
In a toss coin, the only result is a head or a tails. Therefore
that ½ of the time you can win or ½ of the time you can lose. Therefore the
probability of losing three games in a row is:
<span>P = (1/2) * (1/2) * (1/2)
P = 0.125</span>
<span>Therefore the answer is “True”.</span>
simplify
n-2 = 10n/2 + 4/2
n-2 = 5n + 2
subtract 5n to both sides
n - 2 - 5n = 5n + 2 - 5n
simplify
-4n - 2 = 2
add 2 to both sides
-4n - 2 + 2 = 2 + 2
simplify
-4n = 4
divide both sides by -4
-4n/-4 = 4/-4
simplify
n = -1
hope it helps
