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vazorg [7]
3 years ago
8

I need help with this please. Thanks!

Mathematics
1 answer:
den301095 [7]3 years ago
3 0

Answer:

-1

Step-by-step explanation:

2.5 - 3.5x = 8 - 4x - 6

0.5x = 2 - 2.5

0.5x = -0.5

x = -1

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JulsSmile [24]

Answer:

f(x)=-3(x+2)^2-2

Step-by-step explanation: the the FX graph the -3 in my equation represents the decrease(for being negative) in the graph, the positive 2 represents the x axis if that number is positive the negative 3 is going to change the x axis then will end up being negative which is why the x starts off in negative 2, the last number represents the y axis if the y axis is negative 2 the y will start off at -2

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frez [133]

SOLUTION:

Step 1:

From the given question, and comparing the scores in classes A and B

Step 2:

Question one, to know the class which had the better overall result on the exam;

(I) The scores in class A ranges from 65 to 100, while that of class B ranges from 60 to 90. This explains that class A had better results.

(ii) The median of the scores in class A is 85, while the median of the scores in class B is 75, this is another piece of supporting evidence that class A had better results.

Step 3:

Question two, to know the class which had greater variability in the results;

For a better understanding of this question, I need to explain the concept of variability in statistics.

Variability in statistics refers to the difference being exhibited by data points within a data set, as related to each other or as related to the mean. This can be expressed through the range, variance or standard deviation of a data set.

Step 4:

So we need to find the range of scores in each of the two classes and then compare, the class with the greater range has the greater variability.

The Range is the difference between the lowest and highest score (H - L), where H is the highest score and L is the lowest score.

Step 5:

Applying the formula for range stated in step 4;

For Class A; H = 100 and L = 65

For Class B; H = 90 and L = 60

The range for class A; H - L = 100 - 65 = 35

The range for class B; H - L = 90 - 60 = 30

By comparing the range of class A and that of B, it is clear that Class A had a greater range (variability)

CONCLUSION:

Class A had better overall results in the exam and greater variability in the results.

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leonid [27]

Answer:

l=\frac{A-\frac{1}{2} \pi w^2}{2w}

Step-by-step explanation:

We essentially need to solve for l; in other words, we must isolate it to one side.

First, notice that the term \frac{1}{2} \pi w^2 doesn't have any l terms in it, so we can just move this to the left side by subtracting both sides by \frac{1}{2} \pi w^2:

A - \frac{1}{2} \pi w^2 = 2lw

Now, the right side has 2lw, so we must divide both sides by 2w to isolate l:

l=\frac{A-\frac{1}{2} \pi w^2}{2w}

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