To find the value take the b and divide it by two. then square it. here your b value is 2 so 2/2 is 1. squared is. 1.
x° + 90° + 52.6 = 180°
<em>because</em><em> </em><em>a</em><em> </em><em>triangle</em><em> </em><em>adds</em><em> </em><em>up</em><em> </em><em>to</em><em> </em><em>1</em><em>8</em><em>0</em><em>°</em><em> </em><em>and </em><em>that</em><em> </em><em>spec</em><em>ific</em><em> </em><em>triangle</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>right</em><em> </em><em>angle </em><em>triangle</em><em> </em><em>which</em><em> </em><em>means</em><em> </em><em>that</em><em> </em><em>it</em><em> </em><em>consist</em><em>s</em><em> </em><em>of</em><em> </em><em>angle</em><em> </em><em>adding</em><em> </em><em>up</em><em> </em><em>to</em><em> </em><em>9</em><em>0</em><em>°</em>
First you have to multiply -8 to (-4x-1)
which is, -12x+8
then there is -9x you have to add like terms
-12x-9x+8
-21x+8 is your final answer
Answer:
None of these.
Step-by-step explanation:
Let's assume we are trying to figure out if (x-6) is a factor. We got the quotient (x^2+6) and the remainder 13 according to the problem. So we know (x-6) is not a factor because the remainder wasn't zero.
Let's assume we are trying to figure out if (x^2+6) is a factor. The quotient is (x-6) and the remainder is 13 according to the problem. So we know (x^2+6) is not a factor because the remainder wasn't zero.
In order for 13 to be a factor of P, all the terms of P must be divisible by 13. That just means you can reduce it to a form that is not a fraction.
If we look at the first term x^3 and we divide it by 13 we get 
we cannot reduce it so it is not a fraction so 13 is not a factor of P
None of these is the right option.
